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A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?
- a)6:50 P.M.
- b)7:00 P.M.
- c)7:10 P.M.
- d)7:20 P.M.
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A defective watch showed the weird behaviour. It gains 5 seconds per 3...
Given Information:
A defective watch showed the following behaviour:
- It gains 5 seconds per 3 minutes for the first hour.
- It loses 10 seconds per 3 minutes in the second hour.
- It gains 15 seconds per 3 minutes for the next one hour.
- The watch showed the correct time at 7:00 A.M.
To find:
What time did the watch indicate at 7:00 P.M.?
Solution:
Let's calculate the net gain or loss in seconds per minute due to the watch's behaviour in one cycle of 3 hours:
- In the first hour, the watch gains 5/3 seconds per minute.
- In the second hour, the watch loses 10/3 seconds per minute.
- In the third hour, the watch gains 15/3 or 5 seconds per minute.
- Therefore, the net gain or loss in one cycle of 3 hours is (5/3 - 10/3 + 5) = 0 seconds per minute.
This means that the watch shows the correct time after every cycle of 3 hours.
Now, we know that the watch showed the correct time at 7:00 A.M. This means that the time indicated by the watch after every cycle of 3 hours will be a multiple of 3 hours from 7:00 A.M.
So, to find the time indicated by the watch at 7:00 P.M., we need to calculate the number of cycles of 3 hours between 7:00 A.M. and 7:00 P.M.
- Number of hours between 7:00 A.M. and 7:00 P.M. = 12 hours.
- Number of cycles of 3 hours in 12 hours = 12/3 = 4.
So, the time indicated by the watch after 4 cycles of 3 hours from 7:00 A.M. will be the correct time.
Let's calculate the gain or loss in seconds due to the watch's behaviour in these 4 cycles:
- In the first cycle, the watch gains 5 seconds per 3 minutes or 100 seconds in 1 hour.
- In the second cycle, the watch loses 10 seconds per 3 minutes or 200 seconds in 1 hour.
- In the third cycle, the watch gains 15 seconds per 3 minutes or 300 seconds in 1 hour.
- In the fourth cycle, the watch loses 10 seconds per 3 minutes or 200 seconds in 1 hour.
So, the net gain or loss in these 4 cycles of 3 hours is (100 - 200 + 300 - 200) = 0 seconds.
This means that the time indicated by the watch after 4 cycles of 3 hours from 7:00 A.M. will be the correct time, which is 7:00 P.M.
Therefore, the answer is option 'A', i.e. 6:50 P.M.
A defective watch showed the following behaviour:
- It gains 5 seconds per 3 minutes for the first hour.
- It loses 10 seconds per 3 minutes in the second hour.
- It gains 15 seconds per 3 minutes for the next one hour.
- The watch showed the correct time at 7:00 A.M.
To find:
What time did the watch indicate at 7:00 P.M.?
Solution:
Let's calculate the net gain or loss in seconds per minute due to the watch's behaviour in one cycle of 3 hours:
- In the first hour, the watch gains 5/3 seconds per minute.
- In the second hour, the watch loses 10/3 seconds per minute.
- In the third hour, the watch gains 15/3 or 5 seconds per minute.
- Therefore, the net gain or loss in one cycle of 3 hours is (5/3 - 10/3 + 5) = 0 seconds per minute.
This means that the watch shows the correct time after every cycle of 3 hours.
Now, we know that the watch showed the correct time at 7:00 A.M. This means that the time indicated by the watch after every cycle of 3 hours will be a multiple of 3 hours from 7:00 A.M.
So, to find the time indicated by the watch at 7:00 P.M., we need to calculate the number of cycles of 3 hours between 7:00 A.M. and 7:00 P.M.
- Number of hours between 7:00 A.M. and 7:00 P.M. = 12 hours.
- Number of cycles of 3 hours in 12 hours = 12/3 = 4.
So, the time indicated by the watch after 4 cycles of 3 hours from 7:00 A.M. will be the correct time.
Let's calculate the gain or loss in seconds due to the watch's behaviour in these 4 cycles:
- In the first cycle, the watch gains 5 seconds per 3 minutes or 100 seconds in 1 hour.
- In the second cycle, the watch loses 10 seconds per 3 minutes or 200 seconds in 1 hour.
- In the third cycle, the watch gains 15 seconds per 3 minutes or 300 seconds in 1 hour.
- In the fourth cycle, the watch loses 10 seconds per 3 minutes or 200 seconds in 1 hour.
So, the net gain or loss in these 4 cycles of 3 hours is (100 - 200 + 300 - 200) = 0 seconds.
This means that the time indicated by the watch after 4 cycles of 3 hours from 7:00 A.M. will be the correct time, which is 7:00 P.M.
Therefore, the answer is option 'A', i.e. 6:50 P.M.
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Community Answer
A defective watch showed the weird behaviour. It gains 5 seconds per 3...
Therefore in 12 hours from 7:00 Am − 7:00 PM
100 − 200 + 300 - 400 + 500 - 600 + 700 -800 +900 -1000 +1000 − 1200
⇒ (−600 sec)
i.e. 10 min lose ⇒ 6 : 50 PM
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A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer?
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A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer?.
A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer?.
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A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A defective watch showed the weird behaviour. It gains 5 seconds per 3 minutes for first hour, loss 10 seconds per 3 minutes in the second hour, again gains 15 seconds per 3 minutes for next one hour and so on. The watch showed the correct time at 7:00 A.M. What time it indicated at 7:00 P.M.?a)6:50 P.M.b)7:00 P.M.c)7:10 P.M.d)7:20 P.M.Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 10 tests.
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