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A metal ‘M' of moderate reactivity is present as its sulphide ‘X' . On heating in air, ‘X' converts into its oxide ‘Y' and a gas evolves. On heating ‘Y' and ‘X' together, the metal ‘M' is produced. ‘X' and ‘Y' respectively are—
  • a)
    ‘X' = cuprous sulphide, ‘Y' = cuprous oxide
  • b)
    ‘X' = cupric sulphide, ‘Y' = cupric oxide
  • c)
    ‘X' = sodium sulphide, ‘Y' = sodium oxide
  • d)
    ‘X' = calcium sulphide, ‘Y' = calcium oxide
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A metal ‘M of moderate reactivity is present as its sulphide &ls...

X → cuprous sulphide
Y → cuprous oxide
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A metal ‘M of moderate reactivity is present as its sulphide &ls...
A metal is a solid material that is typically hard, shiny, malleable, and a good conductor of heat and electricity. Metals have a wide range of uses and can be found in various industries such as construction, manufacturing, and electronics. Common examples of metals include iron, aluminum, copper, gold, and silver. Metals can be further classified into categories such as ferrous metals (containing iron) and non-ferrous metals (not containing iron). They are often characterized by their metallic bonding, which involves the sharing of electrons between atoms in a lattice structure.
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A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer?
Question Description
A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 10. Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free.
Here you can find the meaning of A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A metal ‘M of moderate reactivity is present as its sulphide ‘X . On heating in air, ‘X converts into its oxide ‘Y and a gas evolves. On heating ‘Y and ‘X together, the metal ‘M is produced. ‘X and ‘Y respectively are—a)‘X = cuprous sulphide, ‘Y = cuprous oxideb)‘X = cupric sulphide, ‘Y = cupric oxidec)‘X = sodium sulphide, ‘Y = sodium oxided)‘X = calcium sulphide, ‘Y = calcium oxideCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 10 tests.
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