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100 mL of a solution containing 0.1 mole of NaOH per litre was mixed with 100 mL solution containing 0.02 mole of H2SO4 per litre. The amount of NaOH in the mixture in grams will be
- a)0.12
- b)0.24
- c)2.4
- d)0.36
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
100 mL of a solution containing 0.1 mole of NaOH per litre was mixed w...
2NaOH + H2SO4 → Na2SO4 + H2O
Milliequivalent of NaOH = 0.1 x 100 x 1 = 10
Milliequivalent of H2SO4 = 0,02 x 100 x 2 = 4
After neutralisation, remaining millimoles of NaOH = 10 - 4 = 6
Mass = 6 x 10-3 x 40 = 0.24 g
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100 mL of a solution containing 0.1 mole of NaOH per litre was mixed w...
To find the amount of NaOH in the mixture, we need to calculate the number of moles of NaOH in each solution and then add them together.
Given:
Volume of NaOH solution = 100 mL = 0.1 L
Molarity of NaOH solution = 0.1 mole/L
Step 1: Calculate the number of moles of NaOH in the first solution.
Number of moles = volume (in liters) x molarity
Number of moles of NaOH in the first solution = 0.1 L x 0.1 mole/L = 0.01 moles
Given:
Volume of H2SO4 solution = 100 mL = 0.1 L
Molarity of H2SO4 solution = 0.02 mole/L
Step 2: Calculate the number of moles of H2SO4 in the second solution.
Number of moles of H2SO4 = volume (in liters) x molarity
Number of moles of H2SO4 in the second solution = 0.1 L x 0.02 mole/L = 0.002 moles
Step 3: Add the number of moles of NaOH and H2SO4 together to find the total amount of NaOH in the mixture.
Total moles of NaOH = moles of NaOH in the first solution + moles of NaOH in the second solution
Total moles of NaOH = 0.01 moles + 0.002 moles = 0.012 moles
Step 4: Convert the moles of NaOH to grams.
To convert moles to grams, we use the formula:
Mass (in grams) = moles x molar mass
Molar mass of NaOH = 22.99 g/mol (atomic mass of Na) + 16.00 g/mol (atomic mass of O) + 1.01 g/mol (atomic mass of H) = 39.00 g/mol
Mass of NaOH in the mixture = 0.012 moles x 39.00 g/mol = 0.468 grams
Therefore, the amount of NaOH in the mixture is 0.468 grams, which is closest to option B) 0.24 grams.
Given:
Volume of NaOH solution = 100 mL = 0.1 L
Molarity of NaOH solution = 0.1 mole/L
Step 1: Calculate the number of moles of NaOH in the first solution.
Number of moles = volume (in liters) x molarity
Number of moles of NaOH in the first solution = 0.1 L x 0.1 mole/L = 0.01 moles
Given:
Volume of H2SO4 solution = 100 mL = 0.1 L
Molarity of H2SO4 solution = 0.02 mole/L
Step 2: Calculate the number of moles of H2SO4 in the second solution.
Number of moles of H2SO4 = volume (in liters) x molarity
Number of moles of H2SO4 in the second solution = 0.1 L x 0.02 mole/L = 0.002 moles
Step 3: Add the number of moles of NaOH and H2SO4 together to find the total amount of NaOH in the mixture.
Total moles of NaOH = moles of NaOH in the first solution + moles of NaOH in the second solution
Total moles of NaOH = 0.01 moles + 0.002 moles = 0.012 moles
Step 4: Convert the moles of NaOH to grams.
To convert moles to grams, we use the formula:
Mass (in grams) = moles x molar mass
Molar mass of NaOH = 22.99 g/mol (atomic mass of Na) + 16.00 g/mol (atomic mass of O) + 1.01 g/mol (atomic mass of H) = 39.00 g/mol
Mass of NaOH in the mixture = 0.012 moles x 39.00 g/mol = 0.468 grams
Therefore, the amount of NaOH in the mixture is 0.468 grams, which is closest to option B) 0.24 grams.
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100 mL of a solution containing 0.1 mole of NaOH per litre was mixed with 100 mL solution containing 0.02 mole of H2SO4 per litre. The amount of NaOH in the mixture in grams will bea)0.12b)0.24c)2.4d)0.36Correct answer is option 'B'. Can you explain this answer?
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100 mL of a solution containing 0.1 mole of NaOH per litre was mixed with 100 mL solution containing 0.02 mole of H2SO4 per litre. The amount of NaOH in the mixture in grams will bea)0.12b)0.24c)2.4d)0.36Correct answer is option 'B'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about 100 mL of a solution containing 0.1 mole of NaOH per litre was mixed with 100 mL solution containing 0.02 mole of H2SO4 per litre. The amount of NaOH in the mixture in grams will bea)0.12b)0.24c)2.4d)0.36Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 100 mL of a solution containing 0.1 mole of NaOH per litre was mixed with 100 mL solution containing 0.02 mole of H2SO4 per litre. The amount of NaOH in the mixture in grams will bea)0.12b)0.24c)2.4d)0.36Correct answer is option 'B'. Can you explain this answer?.
100 mL of a solution containing 0.1 mole of NaOH per litre was mixed with 100 mL solution containing 0.02 mole of H2SO4 per litre. The amount of NaOH in the mixture in grams will bea)0.12b)0.24c)2.4d)0.36Correct answer is option 'B'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about 100 mL of a solution containing 0.1 mole of NaOH per litre was mixed with 100 mL solution containing 0.02 mole of H2SO4 per litre. The amount of NaOH in the mixture in grams will bea)0.12b)0.24c)2.4d)0.36Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 100 mL of a solution containing 0.1 mole of NaOH per litre was mixed with 100 mL solution containing 0.02 mole of H2SO4 per litre. The amount of NaOH in the mixture in grams will bea)0.12b)0.24c)2.4d)0.36Correct answer is option 'B'. Can you explain this answer?.
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