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An object is placed perpendicular to the principalaxis of a convex lens of focal length 20 cm. The distance of the object from the lens is 30 cm. Find(i) the position(ii) the magnification and(iii) the nature of the image formed.
Most Upvoted Answer
An object is placed perpendicular to the principalaxis of a convex len...
1/f=1/v-1/u
and f=20cm u=-30cm
now 1/20=1/v-1/-30
1/20+1/-30=1/v
1/v=1/20-1/30
=3-2/60
=1/60
1/v =1/60
so v=60cm
now m=v/u = 60/-30 =-2 m =-2cm
so nature of img.
real , inverted , beyond C
Community Answer
An object is placed perpendicular to the principalaxis of a convex len...
Position of the Image:
- Given: focal length (f) = 20 cm, object distance (u) = 30 cm
- Using the lens formula: 1/f = 1/v - 1/u
- Substitute the values to find the image distance (v)
- 1/20 = 1/v - 1/30
- Solving the equation gives v = 60 cm

Magnification:
- Magnification (m) = -v/u
- Substitute the values to calculate the magnification
- m = -60/30 = -2
- The negative sign indicates an inverted image

Nature of the Image:
- Since the magnification is negative, the image is inverted
- The image distance (60 cm) is greater than the focal length (20 cm), so the image is real
- Therefore, the image formed is a real and inverted image
In summary, the image is formed at a distance of 60 cm from the lens, with a magnification of -2, indicating an inverted image. The nature of the image is real, as it is located beyond the focal point of the lens.
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An object is placed perpendicular to the principalaxis of a convex lens of focal length 20 cm. The distance of the object from the lens is 30 cm. Find(i) the position(ii) the magnification and(iii) the nature of the image formed.
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