An object is placed perpendicular to the principalaxis of a convex len...
1/f=1/v-1/u
and f=20cm u=-30cm
now 1/20=1/v-1/-30
1/20+1/-30=1/v
1/v=1/20-1/30
=3-2/60
=1/60
1/v =1/60
so v=60cm
now m=v/u = 60/-30 =-2 m =-2cm
so nature of img.
real , inverted , beyond C
An object is placed perpendicular to the principalaxis of a convex len...
Position of the Image:
- Given: focal length (f) = 20 cm, object distance (u) = 30 cm
- Using the lens formula: 1/f = 1/v - 1/u
- Substitute the values to find the image distance (v)
- 1/20 = 1/v - 1/30
- Solving the equation gives v = 60 cm
Magnification:
- Magnification (m) = -v/u
- Substitute the values to calculate the magnification
- m = -60/30 = -2
- The negative sign indicates an inverted image
Nature of the Image:
- Since the magnification is negative, the image is inverted
- The image distance (60 cm) is greater than the focal length (20 cm), so the image is real
- Therefore, the image formed is a real and inverted image
In summary, the image is formed at a distance of 60 cm from the lens, with a magnification of -2, indicating an inverted image. The nature of the image is real, as it is located beyond the focal point of the lens.
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