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When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observe
- a)Brick efflorescence
- b)Dense white fumes
- c)Reddish brown gas
- d)Yellowish green vapours
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
When sodium hydroxide is added to ammonium carbonate salt and then a g...
When sodium hydroxide (NaOH) is added to ammonium carbonate (NH4)2CO3 salt and a glass rod dipped in dilute hydrochloric acid (HCl) is brought near the test tube, we observe dense white fumes.
Explanation:
The reaction between sodium hydroxide and ammonium carbonate can be represented by the following chemical equation:
(NH4)2CO3 + 2NaOH → 2NH3 + 2H2O + Na2CO3
In this reaction, sodium hydroxide reacts with ammonium carbonate to produce ammonia gas (NH3), water (H2O), and sodium carbonate (Na2CO3). The ammonia gas is released as a result of the reaction.
When a glass rod dipped in dilute hydrochloric acid is brought near the test tube, it reacts with the ammonia gas produced in the previous step. The reaction between hydrochloric acid and ammonia can be represented as follows:
NH3 + HCl → NH4Cl
In this reaction, ammonia reacts with hydrochloric acid to form ammonium chloride (NH4Cl). This reaction is highly exothermic and releases heat.
The dense white fumes observed in this reaction are actually ammonium chloride (NH4Cl) being formed as a white solid. The fumes are formed due to the reaction between ammonia and hydrochloric acid. The white solid of ammonium chloride is formed as a result of the combination of ammonia gas and hydrochloric acid vapor.
The reaction between ammonia and hydrochloric acid is a classic example of a neutralization reaction. In this reaction, an acid (HCl) reacts with a base (NH3) to form a salt (NH4Cl) and water (H2O).
In summary, when sodium hydroxide is added to ammonium carbonate and a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observe dense white fumes. These fumes are formed due to the reaction between ammonia gas produced from the reaction between sodium hydroxide and ammonium carbonate, and hydrochloric acid. The reaction between ammonia and hydrochloric acid leads to the formation of ammonium chloride, which appears as dense white fumes.
Explanation:
The reaction between sodium hydroxide and ammonium carbonate can be represented by the following chemical equation:
(NH4)2CO3 + 2NaOH → 2NH3 + 2H2O + Na2CO3
In this reaction, sodium hydroxide reacts with ammonium carbonate to produce ammonia gas (NH3), water (H2O), and sodium carbonate (Na2CO3). The ammonia gas is released as a result of the reaction.
When a glass rod dipped in dilute hydrochloric acid is brought near the test tube, it reacts with the ammonia gas produced in the previous step. The reaction between hydrochloric acid and ammonia can be represented as follows:
NH3 + HCl → NH4Cl
In this reaction, ammonia reacts with hydrochloric acid to form ammonium chloride (NH4Cl). This reaction is highly exothermic and releases heat.
The dense white fumes observed in this reaction are actually ammonium chloride (NH4Cl) being formed as a white solid. The fumes are formed due to the reaction between ammonia and hydrochloric acid. The white solid of ammonium chloride is formed as a result of the combination of ammonia gas and hydrochloric acid vapor.
The reaction between ammonia and hydrochloric acid is a classic example of a neutralization reaction. In this reaction, an acid (HCl) reacts with a base (NH3) to form a salt (NH4Cl) and water (H2O).
In summary, when sodium hydroxide is added to ammonium carbonate and a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observe dense white fumes. These fumes are formed due to the reaction between ammonia gas produced from the reaction between sodium hydroxide and ammonium carbonate, and hydrochloric acid. The reaction between ammonia and hydrochloric acid leads to the formation of ammonium chloride, which appears as dense white fumes.
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Community Answer
When sodium hydroxide is added to ammonium carbonate salt and then a g...
When a glass rod dipped in the ammonia solution is brought near HCl gas, a dense white fume of ammonium chloride is formed.
This is because ammonia reacts with the fumes of HCl to give ammonium chloride.
NH3 + HCl → NH4Cl
This is because ammonia reacts with the fumes of HCl to give ammonium chloride.
NH3 + HCl → NH4Cl
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When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer?
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When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer?.
When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer?.
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When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of When sodium hydroxide is added to ammonium carbonate salt and then a glass rod dipped in dilute hydrochloric acid is brought near the test tube, we observea)Brick efflorescenceb)Dense white fumesc)Reddish brown gasd)Yellowish green vapoursCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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