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. A man has certain note of denomination 20 and 5 which amount to 380. If the number of notes of each kind are interchanged, they amount to 60 less than before. Find the number of notes of each denomination.
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. A man has certain note of denomination 20 and 5 which amount to 380....
Problem: A man has certain notes of denomination 20 and 5 which amount to 380. If the number of notes of each kind are interchanged, they amount to 60 less than before. Find the number of notes of each denomination.

Solution:

Let's assume that the number of notes of denomination 20 is x and the number of notes of denomination 5 is y.

Given, x + y = Total number of notes ...(1)

Also, as per the problem, the total amount of money with the man is:

20x + 5y = 380 ...(2)

Now, let's interchange the notes of both denominations. The new total amount of money with the man will be:

5x + 20y = 380 - 60 = 320

Simplifying the above equation, we get:

x = (320 - 20y)/5 ...(3)

Substituting the value of x from equation (3) in equation (1), we get:

(320 - 20y)/5 + y = Total number of notes

Simplifying the above equation, we get:

y = 12

Substituting the value of y in equation (1), we get:

x = 18

Therefore, the man has 18 notes of denomination 20 and 12 notes of denomination 5.

Answer: The man has 18 notes of denomination 20 and 12 notes of denomination 5.
Community Answer
. A man has certain note of denomination 20 and 5 which amount to 380....
16 notes of rs 20 and 12 notes of rs 5
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. A man has certain note of denomination 20 and 5 which amount to 380. If the number of notes of each kind are interchanged, they amount to 60 less than before. Find the number of notes of each denomination.
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