A bag has Math input errorMath input error in the form of 1 rupee, 50...
According to the given information, the bag contains coins in the ratio of 6:3:2, where 6 represents 1 rupee coins, 3 represents 50 paisa coins, and 2 represents 10 paisa coins.
Let's assume the common ratio as 'x'. Therefore, the number of 1 rupee coins will be 6x, the number of 50 paisa coins will be 3x, and the number of 10 paisa coins will be 2x.
The total value of the coins in the bag can be calculated as follows:
Total value = (Value of 1 rupee coins) + (Value of 50 paisa coins) + (Value of 10 paisa coins)
Since 1 rupee is equal to 100 paisa, the value of 1 rupee coins will be 6x * 100 = 600x paisa.
Similarly, the value of 50 paisa coins will be 3x * 50 = 150x paisa.
The value of 10 paisa coins will be 2x * 10 = 20x paisa.
Therefore, the total value of the coins in the bag is 600x + 150x + 20x = 770x paisa.
Since the ratio of the coins is given in terms of 1 rupee, 50 paisa, and 10 paisa coins, the total value should be a multiple of 100 paisa.
Hence, 770x should be divisible by 100.
Dividing 770x by 100, we get x = 7.7.
Since the number of coins cannot be in decimal form, we need to find the number of coins for the value of x = 7.
The number of 50 paisa coins will be 3x = 3 * 7 = 21.
Therefore, the correct answer is option 'C' - 120.
A bag has Math input errorMath input error in the form of 1 rupee, 50...
Since, 1 Rs : 50 paisa : 10 paisa = 100 : 50 : 10
= 10 : 5 : 1
Let there are 6x,3x and 2x no. of rupee, Rs 1,50 paisa and 10 paisa
According to the question, total money in the bag,
⇒ 6x × 10 + 3x × 5 + 2x × 1 = 30.8 × 100
⇒ 77x = 3080
⇒ x = 40
∴ Number of 50 paise coin = 40 × 3 = 120
Hence, the correct option is (C).