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If a no. x is chosen at random from the numbers -2,-1,0,1,2 then find the probability that x^2<2.
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If a no. x is chosen at random from the numbers -2,-1,0,1,2 then find ...
Probability of x^2 < />

To find the probability that x^2 is less than 2, we need to determine the number of outcomes that satisfy this condition and divide it by the total number of possible outcomes.

Step 1: List all possible outcomes

The given numbers are -2, -1, 0, 1, and 2. So the possible outcomes are:
- x = -2
- x = -1
- x = 0
- x = 1
- x = 2

Step 2: Calculate the square of each outcome

To determine if x^2 is less than 2, we need to square each outcome:
- (-2)^2 = 4
- (-1)^2 = 1
- (0)^2 = 0
- (1)^2 = 1
- (2)^2 = 4

Step 3: Identify outcomes where x^2 < />

The outcomes where x^2 is less than 2 are:
- x = -1
- x = 0
- x = 1

Step 4: Calculate the probability

To find the probability, we need to divide the number of outcomes where x^2 < 2="" by="" the="" total="" number="" of="" possible="" />

Number of outcomes where x^2 < 2="3" (since="" there="" are="" three="" values:="" -1,="" 0,="" />
Total number of possible outcomes = 5 (since there are five values: -2, -1, 0, 1, 2)

Therefore, the probability that x^2 < 2="" is="" />

Conclusion

In this problem, we found the probability that x^2 is less than 2 when a number x is chosen randomly from the set {-2, -1, 0, 1, 2}. By listing out all possible outcomes, calculating the square of each outcome, identifying the outcomes where x^2 < 2,="" and="" dividing="" it="" by="" the="" total="" number="" of="" possible="" outcomes,="" we="" determined="" that="" the="" probability="" is="" 3/5.="" 2,="" and="" dividing="" it="" by="" the="" total="" number="" of="" possible="" outcomes,="" we="" determined="" that="" the="" probability="" is="" />
Community Answer
If a no. x is chosen at random from the numbers -2,-1,0,1,2 then find ...
Is ur question complte? probabilty kis chij ka nikalna hai
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