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Calculate the rectification efficiency of half wave rectifier if input power to rectifier is 150 W and power obtained is 90 W.
  • a)
    60%
  • b)
    50%
  • c)
    40%
  • d)
    80%
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Calculate the rectification efficiency of half wave rectifier if input...
Formula Used:
efficiency (%η) = Po/Pi
Here, Po is the output power
And, Pi is the input power
Application:
Given,
Input AC Power (Pi) = 150 W
Output DC Power (Po) = 90 W
Hence, Efficiency (η) = 90/150 = 0.6 = 60 %
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Community Answer
Calculate the rectification efficiency of half wave rectifier if input...
Rectification Efficiency of Half Wave Rectifier:

Rectification efficiency is defined as the ratio of DC output power to the AC input power of a rectifier. In the case of a half wave rectifier, it is given by the formula:

Rectification Efficiency = (DC output power / AC input power) × 100

Given:
Input power to rectifier = 150 W
Power obtained = 90 W

To calculate the rectification efficiency of the half wave rectifier, we need to substitute the given values into the formula.

Calculation:

Rectification Efficiency = (90 W / 150 W) × 100
= 0.6 × 100
= 60%

Therefore, the rectification efficiency of the half wave rectifier is 60%.

Explanation:

- The rectification efficiency of a rectifier indicates how effectively it converts the input AC power into DC power.
- In a half wave rectifier, only one-half cycle of the input AC waveform is converted into DC while the other half is blocked.
- The output power of the rectifier is the product of the DC voltage and current.
- The input power to the rectifier is the product of the input AC voltage and current.
- The rectification efficiency is calculated by dividing the DC output power by the AC input power and multiplying by 100 to express it as a percentage.
- In this case, the input power to the rectifier is 150 W and the power obtained is 90 W.
- Substituting these values into the rectification efficiency formula gives us a result of 60%.
- This means that the half wave rectifier is able to convert 60% of the input AC power into useful DC power.
- The remaining 40% of the input power is lost as heat in the rectifier or wasted as unused energy.
- Therefore, option A, 60%, is the correct answer.
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Calculate the rectification efficiency of half wave rectifier if input power to rectifier is 150 W and power obtained is 90 W.a)60%b)50%c)40%d)80%Correct answer is option 'A'. Can you explain this answer?
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