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An object is placed 12 cm from a convex lens whose focal length is 10 cm. The image must be.
- a)virtual and enlarged
- b)virtual and reduced in size
- c)real and reduced in size
- d)real and enlarged
Correct answer is option 'D'. Can you explain this answer?
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An object is placed 12 cm from a convex lens whose focal length is 10 ...
Understanding the Lens Formula
The situation involves a convex lens, which is known to converge light rays to form images. To determine the characteristics of the image formed, we can use the lens formula:
1/f = 1/v - 1/u
Where:
- f = focal length of the lens (10 cm)
- u = object distance (12 cm)
- v = image distance (unknown)
Calculating Image Distance
Using the lens formula, we can rearrange it to find v:
1/v = 1/f + 1/u
Substituting the values:
1/v = 1/10 + 1/(-12)
This gives:
1/v = 0.1 - 0.0833 = 0.0167
Now, calculate v:
v ≈ 60 cm
Analyzing the Image Characteristics
1. Image Distance (v): Since v is positive, the image is real and formed on the opposite side of the lens from the object.
2. Magnification (m): The magnification can be calculated using the formula:
m = -v/u
Substituting the values:
m = -60/(-12) = 5
This indicates that the image is enlarged (5 times the size of the object).
Conclusion
Based on the calculations:
- The image is real (as v is positive).
- The image is enlarged (since magnification m > 1).
Thus, the correct answer is option 'D': real and enlarged.
The situation involves a convex lens, which is known to converge light rays to form images. To determine the characteristics of the image formed, we can use the lens formula:
1/f = 1/v - 1/u
Where:
- f = focal length of the lens (10 cm)
- u = object distance (12 cm)
- v = image distance (unknown)
Calculating Image Distance
Using the lens formula, we can rearrange it to find v:
1/v = 1/f + 1/u
Substituting the values:
1/v = 1/10 + 1/(-12)
This gives:
1/v = 0.1 - 0.0833 = 0.0167
Now, calculate v:
v ≈ 60 cm
Analyzing the Image Characteristics
1. Image Distance (v): Since v is positive, the image is real and formed on the opposite side of the lens from the object.
2. Magnification (m): The magnification can be calculated using the formula:
m = -v/u
Substituting the values:
m = -60/(-12) = 5
This indicates that the image is enlarged (5 times the size of the object).
Conclusion
Based on the calculations:
- The image is real (as v is positive).
- The image is enlarged (since magnification m > 1).
Thus, the correct answer is option 'D': real and enlarged.
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An object is placed 12 cm from a convex lens whose focal length is 10 cm. The image must be. a)virtual and enlargedb)virtual and reduced in size c)real and reduced in sized)real and enlargedCorrect answer is option 'D'. Can you explain this answer?
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An object is placed 12 cm from a convex lens whose focal length is 10 cm. The image must be. a)virtual and enlargedb)virtual and reduced in size c)real and reduced in sized)real and enlargedCorrect answer is option 'D'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object is placed 12 cm from a convex lens whose focal length is 10 cm. The image must be. a)virtual and enlargedb)virtual and reduced in size c)real and reduced in sized)real and enlargedCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is placed 12 cm from a convex lens whose focal length is 10 cm. The image must be. a)virtual and enlargedb)virtual and reduced in size c)real and reduced in sized)real and enlargedCorrect answer is option 'D'. Can you explain this answer?.
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