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If a unit positive charge is placed inside a sphere of radius r, then the electric flux through the sphere will be:
- a)ϵor
- b)ϵo/r
- c)ϵo-1
- d)ϵo
Correct answer is option 'C'. Can you explain this answer?
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If a unit positive charge is placed inside a sphere of radius r, then ...
CONCEPT:
Gauss's law:
Gauss's law:
- According to Gauss law, the total electric flux linked with a closed surface called Gaussian surface is 1/ϵo the charge enclosed by the closed surface.
⇒ ϕ = Q/ϵo
Where ϕ = electric flux linked with a closed surface, Q = total charge enclosed in the surface, and ϵo = permittivity
Given Q = 1, and r = radius of the sphere
By the Gauss law, if the total charge enclosed in a closed surface is Q, then the total electric flux associated with it will be given as,
⇒ ϕ = Q/ϵo -----(1)
By equation 1 the total flux linked with the sphere is given as,
Hence, option 3 is correct.
Where ϕ = electric flux linked with a closed surface, Q = total charge enclosed in the surface, and ϵo = permittivity
Given Q = 1, and r = radius of the sphere
By the Gauss law, if the total charge enclosed in a closed surface is Q, then the total electric flux associated with it will be given as,
⇒ ϕ = Q/ϵo -----(1)
By equation 1 the total flux linked with the sphere is given as,
Hence, option 3 is correct.
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If a unit positive charge is placed inside a sphere of radius r, then the electric flux through the sphere will be:a)orb)o/rc)o-1d)oCorrect answer is option 'C'. Can you explain this answer?
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