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Two charges of + 4 μC and -16 μC are separated from each other by a distance of 0.6 m. At what distance should a third charge of + 6 μC be placed from + 4 μC so that net force exerts on it will be zero?
  • a)
    0.4 m
  • b)
    0.6 m
  • c)
    1.2 m
  • d)
    0.3 m
Correct answer is option 'B'. Can you explain this answer?
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Two charges of + 4 μC and -16 μC are separated from each other b...
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Two charges of + 4 μC and -16 μC are separated from each other b...
CONCEPT:
Coulomb’s law: When two charged particles of charges q1 and q2 are separated by a distance r from each other then the electrostatic force between them is directly proportional to the multiplication of charges of two particles and inversely proportional to the square of the distance between them.

Force (F) ∝ q1 × q2  

Where K is a constant = 9 × 109 Nm2/C2 
Calculations:
Consider new charge + 4μC is placed d m apart from old +4 μC charge and (x + 0.6) m apart from -16 μC charge.
Let,
qA = + 4 μC at point A
qB = - 16 μC at point B
qC = + 6 μC at point C

Since, net force on charge qC will zero.
∴ |FCA| = |FCB|
From above concept,

4d2 = (0.6 + d)2
4d2 = 0.36 + d2 + 1.2d
3d2 - 1.2d - 0.36 = 0
d1 = - 0.2 m
d2 = + 0.6 m
Hence, according to option + 0.6 m distance should a third charge of + 6 μC be placed from + 4 μC so that no force exerts on it will be zero.
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Two charges of + 4 μC and -16 μC are separated from each other by a distance of 0.6 m. At what distance should a third charge of + 6 μC be placed from + 4 μC so that net force exerts on it will be zero?a)0.4 mb)0.6 mc)1.2 md)0.3 mCorrect answer is option 'B'. Can you explain this answer?
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