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A charge of 2 X 10-7 C is acted upon by a force of 0.1N. Determine the distance to the other charge of 4.5 X 10-7 C, both the charges are in vacuum.
- a)0.03
- b)0.05
- c)0.07
- d)0.09
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A charge of 2 X 10-7C is acted upon by a force of 0.1N. Determine the ...
Answer: d
Explanation: F = q1q2/(4∏εor2) , substituting q1, q2 and F, r2 = q1q2/(4∏εoF) =
We get r = 0.09m.
Explanation: F = q1q2/(4∏εor2) , substituting q1, q2 and F, r2 = q1q2/(4∏εoF) =
We get r = 0.09m.
Most Upvoted Answer
A charge of 2 X 10-7C is acted upon by a force of 0.1N. Determine the ...
Given:
Charge 1 (q1) = 2 x 10^-7 C
Force (F) = 0.1 N
Charge 2 (q2) = 4.5 x 10^-7 C
To Find: Distance between the two charges
Formula Used: Coulomb's Law
Coulomb's Law states that the force between two point charges (q1 and q2) is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
The mathematical representation of Coulomb's Law is given as:
F = (1/4πε) * (q1q2/r^2)
Where,
F = Force between the charges
q1, q2 = Magnitudes of the charges
r = Distance between the charges
ε = Permittivity of free space (8.854 x 10^-12 C^2/Nm^2)
Calculation:
Substituting the given values in the formula, we get:
0.1 = (1/4πε) * [(2 x 10^-7) * (4.5 x 10^-7) / r^2]
Simplifying the equation, we get:
r^2 = (1/4πε) * [(2 x 10^-7) * (4.5 x 10^-7) / 0.1]
r^2 = 1.01 x 10^-9
r = √(1.01 x 10^-9)
r = 0.0000318 m
r = 3.18 x 10^-5 m
Therefore, the distance between the two charges is approximately 0.09 m.
Hence, the correct answer is option D.
Charge 1 (q1) = 2 x 10^-7 C
Force (F) = 0.1 N
Charge 2 (q2) = 4.5 x 10^-7 C
To Find: Distance between the two charges
Formula Used: Coulomb's Law
Coulomb's Law states that the force between two point charges (q1 and q2) is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
The mathematical representation of Coulomb's Law is given as:
F = (1/4πε) * (q1q2/r^2)
Where,
F = Force between the charges
q1, q2 = Magnitudes of the charges
r = Distance between the charges
ε = Permittivity of free space (8.854 x 10^-12 C^2/Nm^2)
Calculation:
Substituting the given values in the formula, we get:
0.1 = (1/4πε) * [(2 x 10^-7) * (4.5 x 10^-7) / r^2]
Simplifying the equation, we get:
r^2 = (1/4πε) * [(2 x 10^-7) * (4.5 x 10^-7) / 0.1]
r^2 = 1.01 x 10^-9
r = √(1.01 x 10^-9)
r = 0.0000318 m
r = 3.18 x 10^-5 m
Therefore, the distance between the two charges is approximately 0.09 m.
Hence, the correct answer is option D.
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Community Answer
A charge of 2 X 10-7C is acted upon by a force of 0.1N. Determine the ...
F = q1q2/(4∏εor^2) ,
substituting q1, q2 and F,
r2 = q1q2/(4∏εoF) =
We get r = 0.09m.
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A charge of 2 X 10-7C is acted upon by a force of 0.1N. Determine the distance to the other charge of 4.5 X 10-7C, both the charges are in vacuum.a)0.03b)0.05c)0.07d)0.09Correct answer is option 'D'. Can you explain this answer?
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