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A pulse train with a frequency of 1 MHz is counted using a mod-1024 ripple counter built with J-K flip-flops. For proper operation of the counter the maximum permissible propagation delay per flip-flop stage is
- a)100 ns
- b)50 ns
- c)20 ns
- d)10 ns
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A pulse train with a frequency of 1 MHz is counted using a mod-1024 ri...
Concept:
If we pass the input signal to a single T-flip flop, we will get half of the frequency at the output.
Similarly, when we pass the input signal into an n-bit flip flop counter, the output frequency (fout) will be:
Calculation:
Similarly, when we pass the input signal into an n-bit flip flop counter, the output frequency (fout) will be:
Calculation:
Given is a mod-1024 ripple counter which means that it can count 1024 states.
To count 1024 number of flipflop required is:
1024 = 2n
n = 10 flip-flops
tpdff = Propagation delay of flip flops
tpdff = 1/f
tpdff = 10-6 sec.
Propagation delay per flipflop =
= 100 nsec
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A pulse train with a frequency of 1 MHz is counted using a mod-1024 ri...
The maximum permissible propagation delay per flip-flop stage in a mod-1024 ripple counter built with J-K flip-flops can be calculated based on the maximum frequency of the input pulse train and the desired operation of the counter.
Given that the frequency of the input pulse train is 1 MHz, we can calculate the period of each pulse as follows:
Period = 1 / Frequency
= 1 / 1 MHz
= 1 μs
Since the counter is a mod-1024 ripple counter, it will count up to 1024 before resetting to zero. Therefore, the counter needs to complete 1024 clock cycles within the period of the input pulse train in order to properly operate.
To calculate the maximum permissible propagation delay per flip-flop stage, we need to determine the maximum time allowed for each stage of the counter to propagate the signal. This can be calculated by dividing the period of the input pulse train by the number of stages in the counter.
Propagation Delay per Flip-Flop Stage = Period / Number of Stages
In this case, since the counter is a mod-1024 ripple counter, the number of stages is 10 (log2(1024) = 10).
Propagation Delay per Flip-Flop Stage = 1 μs / 10
= 100 ns
Therefore, the maximum permissible propagation delay per flip-flop stage is 100 ns (option A).
In a ripple counter, the output of each flip-flop is connected to the clock input of the next flip-flop in a chain. As a result, the output of each flip-flop is affected by the propagation delay of the previous flip-flop. If the propagation delay per flip-flop stage exceeds the maximum permissible value, the output of the counter may not change at the correct time, leading to incorrect counting.
Hence, it is crucial to ensure that the propagation delay per flip-flop stage is within the specified limit to guarantee proper operation of the counter.
Given that the frequency of the input pulse train is 1 MHz, we can calculate the period of each pulse as follows:
Period = 1 / Frequency
= 1 / 1 MHz
= 1 μs
Since the counter is a mod-1024 ripple counter, it will count up to 1024 before resetting to zero. Therefore, the counter needs to complete 1024 clock cycles within the period of the input pulse train in order to properly operate.
To calculate the maximum permissible propagation delay per flip-flop stage, we need to determine the maximum time allowed for each stage of the counter to propagate the signal. This can be calculated by dividing the period of the input pulse train by the number of stages in the counter.
Propagation Delay per Flip-Flop Stage = Period / Number of Stages
In this case, since the counter is a mod-1024 ripple counter, the number of stages is 10 (log2(1024) = 10).
Propagation Delay per Flip-Flop Stage = 1 μs / 10
= 100 ns
Therefore, the maximum permissible propagation delay per flip-flop stage is 100 ns (option A).
In a ripple counter, the output of each flip-flop is connected to the clock input of the next flip-flop in a chain. As a result, the output of each flip-flop is affected by the propagation delay of the previous flip-flop. If the propagation delay per flip-flop stage exceeds the maximum permissible value, the output of the counter may not change at the correct time, leading to incorrect counting.
Hence, it is crucial to ensure that the propagation delay per flip-flop stage is within the specified limit to guarantee proper operation of the counter.
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A pulse train with a frequency of 1 MHz is counted using a mod-1024 ripple counter built with J-K flip-flops. For proper operation of the counter the maximum permissible propagation delay per flip-flop stage isa)100 nsb)50 nsc)20 nsd)10 nsCorrect answer is option 'A'. Can you explain this answer?
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