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An AM broadcast station is found to be transmitting modulating frequencies up to 5 kHz and the station is allowed to transmit on a frequency of 950 kHz, then what will be the bandwidth (in kHz) allotted to the station?
- a)5
- b)10
- c)20
- d)25
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
An AM broadcast station is found to be transmitting modulating frequen...
To determine the bandwidth allotted to an AM broadcast station, we need to consider the modulating frequencies and the carrier frequency.
Given:
Modulating frequencies = 5 kHz
Carrier frequency = 950 kHz
The bandwidth allotted to the station can be determined using Carson's rule, which states that the bandwidth required for an AM signal is equal to twice the sum of the highest modulating frequency and the frequency deviation.
Formula:
Bandwidth = 2 * (Highest Modulating Frequency + Frequency Deviation)
1. Highest Modulating Frequency:
The given modulating frequencies go up to 5 kHz. Therefore, the highest modulating frequency is 5 kHz.
2. Frequency Deviation:
The frequency deviation is the maximum shift in frequency from the carrier frequency caused by the modulation. In AM, the frequency deviation is equal to the highest modulating frequency. So, the frequency deviation is also 5 kHz.
3. Calculate Bandwidth:
Using the formula,
Bandwidth = 2 * (5 kHz + 5 kHz)
= 2 * 10 kHz
= 20 kHz
Therefore, the bandwidth allotted to the AM broadcast station is 20 kHz.
Hence, the correct answer is option 'C' 20 kHz.
Given:
Modulating frequencies = 5 kHz
Carrier frequency = 950 kHz
The bandwidth allotted to the station can be determined using Carson's rule, which states that the bandwidth required for an AM signal is equal to twice the sum of the highest modulating frequency and the frequency deviation.
Formula:
Bandwidth = 2 * (Highest Modulating Frequency + Frequency Deviation)
1. Highest Modulating Frequency:
The given modulating frequencies go up to 5 kHz. Therefore, the highest modulating frequency is 5 kHz.
2. Frequency Deviation:
The frequency deviation is the maximum shift in frequency from the carrier frequency caused by the modulation. In AM, the frequency deviation is equal to the highest modulating frequency. So, the frequency deviation is also 5 kHz.
3. Calculate Bandwidth:
Using the formula,
Bandwidth = 2 * (5 kHz + 5 kHz)
= 2 * 10 kHz
= 20 kHz
Therefore, the bandwidth allotted to the AM broadcast station is 20 kHz.
Hence, the correct answer is option 'C' 20 kHz.
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Community Answer
An AM broadcast station is found to be transmitting modulating frequen...
Concept:
Standard expression for AM expression for a message signal AmCosωmt is
S(t) = AC(1 + μCosωmt )cos ωct
Where;
ωm → Modulating frequency (rad/sec) = 2πfm
Bandwidth = 2fm
Calculation:
Given;
Modulating frequency (fm) = 5 KHz
Bandwidth = 2fm = (2 × 5) = 10 KHz
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An AM broadcast station is found to be transmitting modulating frequencies up to 5 kHz and the station is allowed to transmit on a frequency of 950 kHz, then what will be the bandwidth (in kHz) allotted to the station?a)5b)10c)20d)25Correct answer is option 'B'. Can you explain this answer?
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