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Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is white with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yt, represent the random variable y(t1)Yt = Ns if transmitted bit bk = 0YK = a + Nk if transmitted bit bk = 1where Nk represents the noise sample value. The noise sample has a probability density function, PN (n) = 0.5αe (This has mean zero and variance 2/α2), Assume transmitted bits lo be equiprobable and threshold z is set to a/2 = 10-6 VQ. The value of the parameter α (in V-1) isa)1010b)107c)1.414 × 10-10d)2 × 1020Correct answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is white with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yt, represent the random variable y(t1)Yt = Ns if transmitted bit bk = 0YK = a + Nk if transmitted bit bk = 1where Nk represents the noise sample value. The noise sample has a probability density function, PN (n) = 0.5αe (This has mean zero and variance 2/α2), Assume transmitted bits lo be equiprobable and threshold z is set to a/2 = 10-6 VQ. The value of the parameter α (in V-1) isa)1010b)107c)1.414 × 10-10d)2 × 1020Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is white with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yt, represent the random variable y(t1)Yt = Ns if transmitted bit bk = 0YK = a + Nk if transmitted bit bk = 1where Nk represents the noise sample value. The noise sample has a probability density function, PN (n) = 0.5αe (This has mean zero and variance 2/α2), Assume transmitted bits lo be equiprobable and threshold z is set to a/2 = 10-6 VQ. The value of the parameter α (in V-1) isa)1010b)107c)1.414 × 10-10d)2 × 1020Correct answer is option 'B'. Can you explain this answer?.

Solutions for Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is white with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yt, represent the random variable y(t1)Yt = Ns if transmitted bit bk = 0YK = a + Nk if transmitted bit bk = 1where Nk represents the noise sample value. The noise sample has a probability density function, PN (n) = 0.5αe (This has mean zero and variance 2/α2), Assume transmitted bits lo be equiprobable and threshold z is set to a/2 = 10-6 VQ. The value of the parameter α (in V-1) isa)1010b)107c)1.414 × 10-10d)2 × 1020Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE). Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.

Here you can find the meaning of Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is white with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yt, represent the random variable y(t1)Yt = Ns if transmitted bit bk = 0YK = a + Nk if transmitted bit bk = 1where Nk represents the noise sample value. The noise sample has a probability density function, PN (n) = 0.5αe (This has mean zero and variance 2/α2), Assume transmitted bits lo be equiprobable and threshold z is set to a/2 = 10-6 VQ. The value of the parameter α (in V-1) isa)1010b)107c)1.414 × 10-10d)2 × 1020Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is white with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yt, represent the random variable y(t1)Yt = Ns if transmitted bit bk = 0YK = a + Nk if transmitted bit bk = 1where Nk represents the noise sample value. The noise sample has a probability density function, PN (n) = 0.5αe (This has mean zero and variance 2/α2), Assume transmitted bits lo be equiprobable and threshold z is set to a/2 = 10-6 VQ. The value of the parameter α (in V-1) isa)1010b)107c)1.414 × 10-10d)2 × 1020Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is white with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yt, represent the random variable y(t1)Yt = Ns if transmitted bit bk = 0YK = a + Nk if transmitted bit bk = 1where Nk represents the noise sample value. The noise sample has a probability density function, PN (n) = 0.5αe (This has mean zero and variance 2/α2), Assume transmitted bits lo be equiprobable and threshold z is set to a/2 = 10-6 VQ. The value of the parameter α (in V-1) isa)1010b)107c)1.414 × 10-10d)2 × 1020Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is white with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yt, represent the random variable y(t1)Yt = Ns if transmitted bit bk = 0YK = a + Nk if transmitted bit bk = 1where Nk represents the noise sample value. The noise sample has a probability density function, PN (n) = 0.5αe (This has mean zero and variance 2/α2), Assume transmitted bits lo be equiprobable and threshold z is set to a/2 = 10-6 VQ. The value of the parameter α (in V-1) isa)1010b)107c)1.414 × 10-10d)2 × 1020Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is white with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yt, represent the random variable y(t1)Yt = Ns if transmitted bit bk = 0YK = a + Nk if transmitted bit bk = 1where Nk represents the noise sample value. The noise sample has a probability density function, PN (n) = 0.5αe (This has mean zero and variance 2/α2), Assume transmitted bits lo be equiprobable and threshold z is set to a/2 = 10-6 VQ. The value of the parameter α (in V-1) isa)1010b)107c)1.414 × 10-10d)2 × 1020Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.