Monthly income of E and R are in the ratio 1:3 and their expenses are ...
Given:
- The monthly income of E and R are in the ratio 1:3.
- The expenses of E and R are in the ratio 19:40.
- E saves Rs 18860 less than R.
- The total amount they save is Rs 36020.
Let's assume the monthly income of E as x and the monthly income of R as y.
Income ratio:
The income ratio of E and R is given as 1:3.
So, we can write the equation as:
x/y = 1/3 ----(1)
Expense ratio:
The expense ratio of E and R is given as 19:40.
So, we can write the equation as:
(1/3) * x / (2/5) * y = 19/40
(5/6) * x / y = 19/40
40 * (5/6) * x = 19 * y
(200/6) * x = 19 * y
100/3 * x = 19 * y ----(2)
Savings:
E saves Rs 18860 less than R.
So, we can write the equation as:
y - x = 18860 ----(3)
Total savings:
The total amount they save is Rs 36020.
So, we can write the equation as:
x + y = 36020 ----(4)
Solving equations (1), (2), (3), and (4) simultaneously will give us the values of x and y.
Solution:
- Multiply equation (2) by 3 to eliminate the fractions:
100 * x = (57/3) * y
100 * x = 19 * y ----(5)
- Add equations (5) and (3) to eliminate y:
100 * x + y = 19 * y + y
100 * x + y = 20 * y ----(6)
- Substitute equation (6) into equation (4):
x + (20 * y) = 36020
x + 20y = 36020 ----(7)
- Solve equations (1) and (7) simultaneously:
x/y = 1/3 ----(1)
x + 20y = 36020 ----(7)
Multiplying equation (1) by 20, we get:
20 * (x/y) = 20 * (1/3)
20x/y = 20/3
20x = 20y/3 ----(8)
Substituting equation (8) into equation (7), we get:
(20y/3) + 20y = 36020
20y + 60y = 36020 * 3
80y = 108060
y = 1350
Substituting the value of y in equation (3), we get:
x = y - 18860
x = 1350 - 18860
x = -17510
Since income cannot be negative, the assumed value of x is incorrect.
Hence, there seems to be an error in the given question. The correct options for the income of E and R cannot be determined with the given information.
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