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A transistor connected in a common base configuration has the following readings IE = 2 mA and IB = 20 μA. Find the current gain α.
  • a)
    0.95
  • b)
    1.98
  • c)
    0.99
  • d)
    0.98
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A transistor connected in a common base configuration has the followin...
ΜA. The current gain (α) of the transistor can be calculated using the formula:

α = IE / IB

Plugging in the values:

α = 2 mA / 20 μA
α = 2000 μA / 20 μA
α = 100

Therefore, the current gain (α) of the transistor in the common base configuration is 100.
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Community Answer
A transistor connected in a common base configuration has the followin...
Current amplification factor: It is defined as the ratio of the output current to the input current. In the common-base configuration, the output current is emitter current IC, whereas the input current is base current IE.
Thus, the ratio of change in collector current to the change in the emitter current is known as the current amplification factor. It is expressed by the α.

Calculation:
Given,
IE = 2 mA
IB = 20 μA = 0.02 mA
From above concept,
IC = 2 mA - 0.02 mA = 1.98 mA
Current amplification factor is given as,
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A transistor connected in a common base configuration has the following readings IE = 2 mA and IB = 20 μA. Find the current gain α.a)0.95b)1.98c)0.99d)0.98Correct answer is option 'C'. Can you explain this answer?
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