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Calculate the hall voltage when the magnetic field is 8 A/m, current is 4 A, width is 5 m and the concentration of carrier is 100000.
- a)4.125 V
- b)0.3125 V
- c)4.2 V
- d)0.4 V
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
Calculate the hall voltage when the magnetic field is 8 A/m, current i...
To calculate the Hall voltage, we can use the equation:
VH = B * I * d / (n * e)
Where:
VH is the Hall voltage
B is the magnetic field strength
I is the current
d is the width of the conductor
n is the concentration of charge carriers
e is the charge of an electron
Given:
B = 8 A/m
I = 4 A
d = 5 m
n = 100000
e = 1.6 x 10^-19 C
Substituting the given values into the equation, we have:
VH = (8 A/m) * (4 A) * (5 m) / (100000 * 1.6 x 10^-19 C)
Simplifying the equation:
VH = (32 A^2 m) / (1.6 x 10^-14 C)
VH = 32 / (1.6 x 10^-14) V
VH = 20 x 10^14 V
VH = 2 x 10^15 V
Converting this value to scientific notation:
VH = 2 V
Therefore, the Hall voltage in this case is 2 V. None of the given options match the calculated value, so it seems that there may be an error in the question or the options provided.
VH = B * I * d / (n * e)
Where:
VH is the Hall voltage
B is the magnetic field strength
I is the current
d is the width of the conductor
n is the concentration of charge carriers
e is the charge of an electron
Given:
B = 8 A/m
I = 4 A
d = 5 m
n = 100000
e = 1.6 x 10^-19 C
Substituting the given values into the equation, we have:
VH = (8 A/m) * (4 A) * (5 m) / (100000 * 1.6 x 10^-19 C)
Simplifying the equation:
VH = (32 A^2 m) / (1.6 x 10^-14 C)
VH = 32 / (1.6 x 10^-14) V
VH = 20 x 10^14 V
VH = 2 x 10^15 V
Converting this value to scientific notation:
VH = 2 V
Therefore, the Hall voltage in this case is 2 V. None of the given options match the calculated value, so it seems that there may be an error in the question or the options provided.
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Community Answer
Calculate the hall voltage when the magnetic field is 8 A/m, current i...
Concept:
The hall voltage VA is given by:
ρc: Charge density = ne
RH: Hall coefficient
W is the side across which the magnetic field is applied.
n is the carrier concentration
e is the electron charge
Calculation:
W = Thickness = 5 m, I = 4 A, B = 8 A/m, n = 100000
ρc = ne
ρc = 100000 × 1.6 × 10-19
ρc = 1.6 × 10-14
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Calculate the hall voltage when the magnetic field is 8 A/m, current is 4 A, width is 5 m and the concentration of carrier is 100000.a)4.125 Vb)0.3125 Vc)4.2 Vd)0.4 VCorrect answer is option 'D'. Can you explain this answer?
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