Electric Field of 1 V/m is applied to a Boron doped Silicon semiconduc...
Concept:
For a semiconductor slab doped with excess carriers and placed in an electric field, the current equation is given by:-
J = σ E
Where J = Current Density
σ = Conductivity of the semiconductor defined as:
σ = qnμn + qpμp
n = excess electrons contributing to the current conduction.
p = excess holes contributing to the current conduction.
Also,
the Resistivity is defined as the reciprocal of conductivity.Calculation:
The given Si semiconductor is doped with Boron impurity.
So, Na = 1016 /cm3 (p-type)
q = 1.6 × 10-19 C
μn = 1300 cm2/V-s and μp = 500 cm2/V-s
The excess electrons is given by;
Since, Na ≫ ni, we can assume that the conduction current exists only because of acceptor impunities, i.e. because of Na.
So, σ = q Na μp
ρ = Resistivity of the given Slab
Putting on the respective values, we get: