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There are two concentric circles whose areas are in the 9:16 and the difference between their diameters is 4cm. What is the area of the outer circle?
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There are two concentric circles whose areas are in the 9:16 and the d...
Problem:
There are two concentric circles whose areas are in the 9:16 and the difference between their diameters is 4cm. What is the area of the outer circle?

Solution:
Let the radii of the two concentric circles be r and R, where R>r.
Given that the ratio of their areas is 9:16, we have:
Area of inner circle / Area of outer circle = 9/16

Step 1:
Using the formula for the area of a circle, we can write:
πr² / πR² = 9/16

Step 2:
Simplifying this expression, we get:
r² / R² = 9/16

Step 3:
Taking the square root of both sides, we have:
r / R = 3/4

Step 4:
Since we know that the difference between their diameters is 4cm, we can write:
2R - 2r = 4

Step 5:
Simplifying this expression, we get:
R - r = 2

Step 6:
Solving the system of equations formed by steps 3 and 5, we get:
R = 8cm and r = 6cm

Step 7:
Finally, we can find the area of the outer circle using the formula for the area of a circle:
Area of outer circle = πR² = π(8)² = 64π square cm

Therefore, the area of the outer circle is 64π square cm.
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There are two concentric circles whose areas are in the 9:16 and the d...
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There are two concentric circles whose areas are in the 9:16 and the difference between their diameters is 4cm. What is the area of the outer circle?
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