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when hydrogen sulphide gas is passed through a blue solution of copper sulphate a black precipitate of copper sulphate is obtained and the sulphuric acid so formed remains in the solution the reaction is an example of
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when hydrogen sulphide gas is passed through a blue solution of copper...
Reaction between hydrogen sulphide gas and copper sulphate
When hydrogen sulphide gas (H2S) is passed through a blue solution of copper sulphate (CuSO4), a black precipitate of copper sulphide (CuS) is obtained. This reaction is an example of a double displacement reaction.
Double displacement reaction:
A double displacement reaction occurs when the positive ions and negative ions of two compounds switch places, forming two new compounds. In this case, the hydrogen sulphide gas reacts with the copper sulphate solution to form copper sulphide and sulphuric acid.
Equation for the reaction:
The equation for the reaction between hydrogen sulphide gas and copper sulphate can be written as:
H2S + CuSO4 → CuS + H2SO4
Explanation of the reaction:
- Hydrogen sulphide gas (H2S) is a reducing agent. It oxidizes itself and reduces the copper ions (Cu2+) present in the copper sulphate solution.
- The hydrogen sulphide gas reacts with the copper sulphate solution, resulting in the formation of copper sulphide (CuS) as a black precipitate.
- The copper sulphide is insoluble in water and appears as a solid black precipitate in the solution.
- At the same time, the hydrogen sulphide gas oxidizes itself to form sulphuric acid (H2SO4). The sulphuric acid remains in the solution.
- The reaction can be represented as a double displacement reaction because the positive ions (Cu2+) and negative ions (SO4 2-) in the copper sulphate switch places with the positive ions (H+) and negative ions (S2-) in the hydrogen sulphide gas.
- The overall reaction results in the formation of copper sulphide and sulphuric acid.
Conclusion:
The reaction between hydrogen sulphide gas and copper sulphate results in the formation of a black precipitate of copper sulphide and sulphuric acid in the solution. This reaction is an example of a double displacement reaction, where the positive and negative ions of the two compounds switch places.
When hydrogen sulphide gas (H2S) is passed through a blue solution of copper sulphate (CuSO4), a black precipitate of copper sulphide (CuS) is obtained. This reaction is an example of a double displacement reaction.
Double displacement reaction:
A double displacement reaction occurs when the positive ions and negative ions of two compounds switch places, forming two new compounds. In this case, the hydrogen sulphide gas reacts with the copper sulphate solution to form copper sulphide and sulphuric acid.
Equation for the reaction:
The equation for the reaction between hydrogen sulphide gas and copper sulphate can be written as:
H2S + CuSO4 → CuS + H2SO4
Explanation of the reaction:
- Hydrogen sulphide gas (H2S) is a reducing agent. It oxidizes itself and reduces the copper ions (Cu2+) present in the copper sulphate solution.
- The hydrogen sulphide gas reacts with the copper sulphate solution, resulting in the formation of copper sulphide (CuS) as a black precipitate.
- The copper sulphide is insoluble in water and appears as a solid black precipitate in the solution.
- At the same time, the hydrogen sulphide gas oxidizes itself to form sulphuric acid (H2SO4). The sulphuric acid remains in the solution.
- The reaction can be represented as a double displacement reaction because the positive ions (Cu2+) and negative ions (SO4 2-) in the copper sulphate switch places with the positive ions (H+) and negative ions (S2-) in the hydrogen sulphide gas.
- The overall reaction results in the formation of copper sulphide and sulphuric acid.
Conclusion:
The reaction between hydrogen sulphide gas and copper sulphate results in the formation of a black precipitate of copper sulphide and sulphuric acid in the solution. This reaction is an example of a double displacement reaction, where the positive and negative ions of the two compounds switch places.
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