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The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are respectively
- a)3 and +3
- b)3 and 0
- c)6 and +3
- d)4 and +2
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are ...
As the number of atoms of the ligands that are directly bound to the central metal is known as coordination number. It is six here (see in figure).
Oxidation state :
Let oxidation state of Cr be x.
⇒ 3(+1) + x + 3(−2) = 0
⇒ 3 + x − 6=0
⇒ x = +3
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The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are ...
The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are 6 and 3, respectively.
Explanation:
Coordination Number:
The coordination number refers to the number of ligands that are directly bonded to the central metal ion. In the given compound K3Cr(C2O4)3, there are six oxalate ligands (C2O4) that are directly bonded to the central chromium (Cr) ion. Therefore, the coordination number of Cr is 6.
Oxidation State:
The oxidation state of an element indicates the number of electrons that are gained, lost, or shared by the element during the formation of a compound. To determine the oxidation state of Cr in K3Cr(C2O4)3, we need to consider the known oxidation states of the other elements in the compound.
K (potassium) is in Group 1 of the periodic table and has an oxidation state of +1.
O (oxygen) is in Group 16 of the periodic table and generally has an oxidation state of -2.
C (carbon) in oxalate (C2O4) has an oxidation state of -2.
Using this information, we can calculate the oxidation state of Cr:
3(K) + 3(+1) + x + 3(C2O4) + 3(-2) = 0
3 + 3 + x - 6 = 0
x - 3 = 0
x = +3
Therefore, the oxidation state of Cr in K3Cr(C2O4)3 is +3.
Summary:
In K3Cr(C2O4)3, the coordination number of Cr is 6 because it is bonded to six oxalate ligands. The oxidation state of Cr is +3, which is determined by considering the known oxidation states of the other elements in the compound.
Explanation:
Coordination Number:
The coordination number refers to the number of ligands that are directly bonded to the central metal ion. In the given compound K3Cr(C2O4)3, there are six oxalate ligands (C2O4) that are directly bonded to the central chromium (Cr) ion. Therefore, the coordination number of Cr is 6.
Oxidation State:
The oxidation state of an element indicates the number of electrons that are gained, lost, or shared by the element during the formation of a compound. To determine the oxidation state of Cr in K3Cr(C2O4)3, we need to consider the known oxidation states of the other elements in the compound.
K (potassium) is in Group 1 of the periodic table and has an oxidation state of +1.
O (oxygen) is in Group 16 of the periodic table and generally has an oxidation state of -2.
C (carbon) in oxalate (C2O4) has an oxidation state of -2.
Using this information, we can calculate the oxidation state of Cr:
3(K) + 3(+1) + x + 3(C2O4) + 3(-2) = 0
3 + 3 + x - 6 = 0
x - 3 = 0
x = +3
Therefore, the oxidation state of Cr in K3Cr(C2O4)3 is +3.
Summary:
In K3Cr(C2O4)3, the coordination number of Cr is 6 because it is bonded to six oxalate ligands. The oxidation state of Cr is +3, which is determined by considering the known oxidation states of the other elements in the compound.
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The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are respectivelya)3 and +3b)3 and 0c)6 and +3d)4 and +2Correct answer is option 'C'. Can you explain this answer?
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The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are respectivelya)3 and +3b)3 and 0c)6 and +3d)4 and +2Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are respectivelya)3 and +3b)3 and 0c)6 and +3d)4 and +2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are respectivelya)3 and +3b)3 and 0c)6 and +3d)4 and +2Correct answer is option 'C'. Can you explain this answer?.
The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are respectivelya)3 and +3b)3 and 0c)6 and +3d)4 and +2Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are respectivelya)3 and +3b)3 and 0c)6 and +3d)4 and +2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coordination number and oxidation state of Cr in K3Cr(C2O4)3 are respectivelya)3 and +3b)3 and 0c)6 and +3d)4 and +2Correct answer is option 'C'. Can you explain this answer?.
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