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Enthalpy change for the reaction,
4H(g) → 2H2(g) is −869.6kJ
The dissociation energy of H - H bond is
- a)- 434.8 kJ
- b)- 896.6 kJ
- c)+ 434.8 kJ
- d)+ 217.4 kJ
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Enthalpy change for the reaction,4H(g) → 2H2(g) is −869.6kJThe dissoc...
Enthalpy change for the reaction, 4H(g) → 2H2(g) is −869.6kJ. The dissociation energy of H-H bond can be calculated using the following equation:
ΔH = 4(D(H-H)) - 2(D(H-H2))
Where ΔH is the enthalpy change for the reaction, D(H-H) is the dissociation energy of the H-H bond, and D(H-H2) is the bond energy of the H-H bond in H2.
Substituting the given values, we get:
-869.6 kJ = 4(D(H-H)) - 2(436.4 kJ/mol)
Simplifying the equation, we get:
D(H-H) = 434.8 kJ/mol
Therefore, the dissociation energy of the H-H bond is 434.8 kJ/mol, which is option C.
ΔH = 4(D(H-H)) - 2(D(H-H2))
Where ΔH is the enthalpy change for the reaction, D(H-H) is the dissociation energy of the H-H bond, and D(H-H2) is the bond energy of the H-H bond in H2.
Substituting the given values, we get:
-869.6 kJ = 4(D(H-H)) - 2(436.4 kJ/mol)
Simplifying the equation, we get:
D(H-H) = 434.8 kJ/mol
Therefore, the dissociation energy of the H-H bond is 434.8 kJ/mol, which is option C.
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Community Answer
Enthalpy change for the reaction,4H(g) → 2H2(g) is −869.6kJThe dissoc...
The dissociation energy of H - H bond is 869.6/2 = 434.8 kJ
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Enthalpy change for the reaction,4H(g) → 2H2(g) is −869.6kJThe dissociation energy of H - H bond isa)- 434.8 kJb)- 896.6 kJc)+ 434.8 kJd)+ 217.4 kJCorrect answer is option 'C'. Can you explain this answer?
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Enthalpy change for the reaction,4H(g) → 2H2(g) is −869.6kJThe dissociation energy of H - H bond isa)- 434.8 kJb)- 896.6 kJc)+ 434.8 kJd)+ 217.4 kJCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Enthalpy change for the reaction,4H(g) → 2H2(g) is −869.6kJThe dissociation energy of H - H bond isa)- 434.8 kJb)- 896.6 kJc)+ 434.8 kJd)+ 217.4 kJCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Enthalpy change for the reaction,4H(g) → 2H2(g) is −869.6kJThe dissociation energy of H - H bond isa)- 434.8 kJb)- 896.6 kJc)+ 434.8 kJd)+ 217.4 kJCorrect answer is option 'C'. Can you explain this answer?.
Enthalpy change for the reaction,4H(g) → 2H2(g) is −869.6kJThe dissociation energy of H - H bond isa)- 434.8 kJb)- 896.6 kJc)+ 434.8 kJd)+ 217.4 kJCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Enthalpy change for the reaction,4H(g) → 2H2(g) is −869.6kJThe dissociation energy of H - H bond isa)- 434.8 kJb)- 896.6 kJc)+ 434.8 kJd)+ 217.4 kJCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Enthalpy change for the reaction,4H(g) → 2H2(g) is −869.6kJThe dissociation energy of H - H bond isa)- 434.8 kJb)- 896.6 kJc)+ 434.8 kJd)+ 217.4 kJCorrect answer is option 'C'. Can you explain this answer?.
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