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A 3-ф synchronous generator has a direct axis synchronous reactance of 0.8 pu and quadrature axis synchronous reactance of 0.5 pu. The generator is supplying full load at 0.8 pf lag at 1 pu terminal voltage. The power angle in degrees is _____.
- a)540
- b)17.10
- c)90.90
- d)7.120
Correct answer is option 'B'. Can you explain this answer?
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A 3-ф synchronous generator has a direct axis synchronous reactance ...
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A 3-ф synchronous generator has a direct axis synchronous reactance ...
Given data:
- Direct axis synchronous reactance (Xd) = 0.8 pu
- Quadrature axis synchronous reactance (Xq) = 0.5 pu
- Power factor (pf) = 0.8 lagging
- Terminal voltage (Vt) = 1 pu
Calculating power angle:
1. The power angle (δ) can be calculated using the formula:
\[ \delta = \cos^{-1} (pf) \]
2. Given that the power factor (pf) is 0.8 lagging, we can substitute the value in the formula:
\[ \delta = \cos^{-1} (0.8) = 36.87 degrees \]
3. However, the above value is the electrical power angle. The mechanical power angle (δm) is given by:
\[ \delta_m = \delta - \tan^{-1} \left( \frac{Xq}{Xd} \right) \]
4. Substituting the values of Xd, Xq, and δ in the formula:
\[ \delta_m = 36.87 - \tan^{-1} \left( \frac{0.5}{0.8} \right) \]
\[ \delta_m = 36.87 - 33.13 = 3.74 degrees \]
Therefore, the power angle in degrees is approximately 3.74 degrees.
- Direct axis synchronous reactance (Xd) = 0.8 pu
- Quadrature axis synchronous reactance (Xq) = 0.5 pu
- Power factor (pf) = 0.8 lagging
- Terminal voltage (Vt) = 1 pu
Calculating power angle:
1. The power angle (δ) can be calculated using the formula:
\[ \delta = \cos^{-1} (pf) \]
2. Given that the power factor (pf) is 0.8 lagging, we can substitute the value in the formula:
\[ \delta = \cos^{-1} (0.8) = 36.87 degrees \]
3. However, the above value is the electrical power angle. The mechanical power angle (δm) is given by:
\[ \delta_m = \delta - \tan^{-1} \left( \frac{Xq}{Xd} \right) \]
4. Substituting the values of Xd, Xq, and δ in the formula:
\[ \delta_m = 36.87 - \tan^{-1} \left( \frac{0.5}{0.8} \right) \]
\[ \delta_m = 36.87 - 33.13 = 3.74 degrees \]
Therefore, the power angle in degrees is approximately 3.74 degrees.
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A 3-ф synchronous generator has a direct axis synchronous reactance of 0.8 pu and quadrature axis synchronous reactance of 0.5 pu. The generator is supplying full load at 0.8 pf lag at 1 pu terminal voltage. The power angle in degrees is _____.a)540b)17.10c)90.90d)7.120Correct answer is option 'B'. Can you explain this answer?
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A 3-ф synchronous generator has a direct axis synchronous reactance of 0.8 pu and quadrature axis synchronous reactance of 0.5 pu. The generator is supplying full load at 0.8 pf lag at 1 pu terminal voltage. The power angle in degrees is _____.a)540b)17.10c)90.90d)7.120Correct answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 3-ф synchronous generator has a direct axis synchronous reactance of 0.8 pu and quadrature axis synchronous reactance of 0.5 pu. The generator is supplying full load at 0.8 pf lag at 1 pu terminal voltage. The power angle in degrees is _____.a)540b)17.10c)90.90d)7.120Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 3-ф synchronous generator has a direct axis synchronous reactance of 0.8 pu and quadrature axis synchronous reactance of 0.5 pu. The generator is supplying full load at 0.8 pf lag at 1 pu terminal voltage. The power angle in degrees is _____.a)540b)17.10c)90.90d)7.120Correct answer is option 'B'. Can you explain this answer?.
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