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A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.
Correct answer is '424.5'. Can you explain this answer?
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A 230/460 V transformer has a primary resistance of 0.2 Ω and reactan...
Calculating Secondary Voltage of Transformer
Given:
Calculating Secondary Voltage:
Therefore, the secondary voltage when supplying 10 A at 0.8 p.f. lagging is 424.5 V (
Given:
- Primary voltage (Vp) = 230 V/460 V
- Primary resistance (Rp) = 0.2 Ω
- Primary reactance (Xp) = 0.5 Ω
- Secondary resistance (Rs) = 0.75 Ω
- Secondary reactance (Xs) = 1.8 Ω
- Load current (I) = 10 A
- Power factor (PF) = 0.8 lagging
Calculating Secondary Voltage:
- Calculate the impedance of the load (Z) using the power factor formula:
PF = cos(θ) = Real Power/Apparent Power = P/S
where:
P = Real Power
S = Apparent Power
θ = Angle between current and voltage
cos(θ) = PF = 0.8 lagging
Therefore, cos(θ) = 0.8
θ = cos⁻¹(0.8) = 36.87°
Real Power = I*Vp*cos(θ) = 10*230*cos(36.87°) = 1809.4 W
Apparent Power = I*Vp = 10*230 = 2300 VA
So, PF = P/S = 1809.4/2300 = 0.786
Therefore, the impedance of the load (Z) = Vp/I*PF = 230/(10*0.8) = 28.75 Ω - Calculate the total impedance (ZT) of the transformer using the primary and secondary resistances and reactances:
ZT = sqrt((Rp+Rs)² + (Xp+Xs)²) = sqrt((0.2+0.75)² + (0.5+1.8)²) = 2.149 Ω - Calculate the secondary voltage (Vs) using the voltage ratio formula:
Vs/Vp = Ns/Np
where:
Ns = number of turns in the secondary coil
Np = number of turns in the primary coil
Since the transformer is rated 230/460 V, the voltage ratio is 2:
Vs/Vp = 2/1
Vs = Vp*2 = 230*2 = 460 V - Calculate the secondary current (Is) using Ohm's Law:
Is = Vs/ZT = 460/2.149 = 214.1 A - Calculate the voltage drop across the secondary resistance and reactance:
VRs = Is*Rs = 214.1*0.75 = 160.6 V
VXs = Is*Xs = 214.1*1.8 = 385.4 V - Calculate the secondary voltage under load:
Vs(load) = Vs - VRs - VXs = 460 - 160.6 - 385.4 = 424 V
Therefore, the secondary voltage when supplying 10 A at 0.8 p.f. lagging is 424.5 V (
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A 230/460 V transformer has a primary resistance of 0.2 Ω and reactan...
Given: R1 = 0.2 Ω, X1=0.5 Ω, R2=0.75 Ω, X2=1.8 Ω
I2=10A, pf=0.8lag, V1/V2= 230/460 V
Transformation ratio, K=460/230=2
Resistance referred to secondary, R02 =R2+K2 R1
⇒R02=0.75+22*0.2=1.55 Ω
Reactance referred to secondary,X02=X2+ K2 X1= 1.8+22*0.5=3.8 Ω
Voltage drop = I2(R02cosф +sinф )= 10*(1.55*0.8+3.8*0.6) =35.2V
∴ Secondary terminal voltage =460 - 35.2= 424.8V
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A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer?
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A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer?.
A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer?.
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A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer?, a detailed solution for A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer? has been provided alongside types of A 230/460 V transformer has a primary resistance of 0.2 Ω and reactance of 0.5 Ω and the corresponding values for the secondary are 0.75 Ω and 1.8 Ω respectively. The secondary voltage when supplying 10 A at 0.8 p.f. lagging is ___________ V.Correct answer is '424.5'. Can you explain this answer? theory, EduRev gives you an
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