NEET Exam > NEET Questions > A body moving in a straight line with consta...
Start Learning for Free
A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?
- a)50 m
- b)60 m
- c)70 m
- d)80 m
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A body moving in a straight line with constant acceleration of 10 ms-...
The distance covered in the nth second is given by
∴ 
or 40 = u + 7/2 × 10 or u = 40 - 35
= 5 ms-1
∴ 
which gives S6 = 60 m
Thus, the correct answer is option (b).
Free Test
FREE
| Start Free Test |
Community Answer
A body moving in a straight line with constant acceleration of 10 ms-...
To find the distance covered by a body in the 6th second, we need to use the equations of motion.
Given:
Acceleration (a) = 10 m/s^2
Distance covered in the 4th second = 40 m
We know that the distance covered in a given time interval can be calculated using the equation:
Distance (s) = ut + 1/2at^2
where u is the initial velocity, t is the time, and a is the acceleration.
Let's find the initial velocity of the body in order to calculate the distance covered in the 6th second.
Initial velocity (u) can be found using the equation:
Distance (s) = ut + 1/2at^2
Rearranging the equation, we get:
u = (2s - at^2) / (2t)
Substituting the values, we have:
u = (2 * 40 - 10 * 4^2) / (2 * 4)
= (80 - 160) / 8
= -80 / 8
= -10 m/s
Since the velocity is negative, it means the body is moving in the opposite direction.
Now, we can calculate the distance covered in the 6th second using the equation:
Distance (s) = ut + 1/2at^2
Substituting the values, we have:
s = (-10 * 6) + 1/2 * 10 * 6^2
= -60 + 1/2 * 10 * 36
= -60 + 1/2 * 360
= -60 + 180
= 120 m
Since distance cannot be negative, the magnitude of the distance covered in the 6th second is 120 m.
Therefore, the correct answer is option B) 60 m.
Given:
Acceleration (a) = 10 m/s^2
Distance covered in the 4th second = 40 m
We know that the distance covered in a given time interval can be calculated using the equation:
Distance (s) = ut + 1/2at^2
where u is the initial velocity, t is the time, and a is the acceleration.
Let's find the initial velocity of the body in order to calculate the distance covered in the 6th second.
Initial velocity (u) can be found using the equation:
Distance (s) = ut + 1/2at^2
Rearranging the equation, we get:
u = (2s - at^2) / (2t)
Substituting the values, we have:
u = (2 * 40 - 10 * 4^2) / (2 * 4)
= (80 - 160) / 8
= -80 / 8
= -10 m/s
Since the velocity is negative, it means the body is moving in the opposite direction.
Now, we can calculate the distance covered in the 6th second using the equation:
Distance (s) = ut + 1/2at^2
Substituting the values, we have:
s = (-10 * 6) + 1/2 * 10 * 6^2
= -60 + 1/2 * 10 * 36
= -60 + 1/2 * 360
= -60 + 180
= 120 m
Since distance cannot be negative, the magnitude of the distance covered in the 6th second is 120 m.
Therefore, the correct answer is option B) 60 m.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer?
Question Description
A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer?.
A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A body moving in a straight line with constant acceleration of 10 ms-2 covers a distance of 40 m in the 4th second. How much distance will it cover in the 6th second?a)50 mb)60 mc)70 md)80 mCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup