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The phase difference between current and voltage in an AC circuit is π/4 radian. If the frequency of the AC used is 50 Hz, then the phase difference is equivalent to the time difference
  • a)
    0.78 ms
  • b)
    7.8 ms
  • c)
    0.25 ms
  • d)
    2.5 ms
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The phase difference between current and voltage in an AC circuit is ...
The phase difference between current and voltage in an AC circuit can be determined by the formula:

Phase Difference (in radians) = 2π × Frequency (in Hz) × Time Difference (in seconds)

Given that the phase difference is π/4 radians and the frequency is 50 Hz, we can rearrange the formula to solve for the time difference:

Time Difference (in seconds) = Phase Difference (in radians) / (2π × Frequency (in Hz))

Substituting the given values:

Time Difference (in seconds) = π/4 / (2π × 50)

Simplifying the expression:

Time Difference (in seconds) = 1 / (8 × 50) = 1 / 400

To convert the time difference to milliseconds, we can multiply it by 1000:

Time Difference (in milliseconds) = (1 / 400) × 1000 = 2.5 ms

Therefore, the equivalent time difference for a phase difference of π/4 radians at a frequency of 50 Hz is 2.5 ms.
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Community Answer
The phase difference between current and voltage in an AC circuit is ...
ω = 2πf = 100π.
= 2.5 × 10–3 s
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