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If 2% of the main current is to be passed through the galvanometer of resistance G. the resistance of shunt required is
  • a)
    G/49
  • b)
    49 G
  • c)
    G / 50
  • d)
    50 G
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If 2% of the main current is to be passed through the galvanometer of ...

Calculation of Shunt Resistance

To pass 2% of the main current through the galvanometer of resistance G, we need to use a shunt resistor.

Formula:
The formula to calculate the shunt resistance required is given by:
\( \frac{I_g}{I_s} = \frac{G}{R_s+G} \)

Given:
\( \frac{I_g}{I} = 2\% = 0.02 \) (2% of the main current)
\( I_s = I - I_g = I - 0.02I = 0.98I \) (Current through the shunt resistor)

Solving for Shunt Resistance:

Now, substituting the values in the formula:
\( \frac{0.02I}{0.98I} = \frac{G}{R_s+G} \)
\( R_s = \frac{G}{49} \)

Therefore, the resistance of the shunt required is \( \frac{G}{49} \), which corresponds to option 'A'.
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If 2% of the main current is to be passed through the galvanometer of resistance G. the resistance of shunt required isa)G/49 b)49 Gc)G / 50d) 50 GCorrect answer is option 'A'. Can you explain this answer?
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