Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > The sending-end and receiving-end voltages of...
Start Learning for Free
The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)
Correct answer is '1259.5'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The sending-end and receiving-end voltages of a three-phase transmissi...
Free Test
FREE
| Start Free Test |
Community Answer
The sending-end and receiving-end voltages of a three-phase transmissi...
Given data:
- Sending-end and receiving-end voltages: 230 kV
- Per phase line impedance: 14 ohm
- Load: 200 MW
To find:
- Maximum steady-state power that can be transmitted (MW/phase)
Formula:
The maximum steady-state power that can be transmitted over a transmission line is given by the formula:
\[
P_{\text{max}} = \frac{{V^2}}{{Z}}
\]
where:
- \(P_{\text{max}}\) is the maximum power that can be transmitted
- \(V\) is the sending/receiving voltage
- \(Z\) is the line impedance
Calculation:
Substituting the given values into the formula, we have:
\[
P_{\text{max}} = \frac{{(230 \text{ kV})^2}}{{14 \Omega}}
\]
Converting the voltage to volts and simplifying, we get:
\[
P_{\text{max}} = \frac{{(230 \times 10^3 \text{ V})^2}}{{14 \Omega}}
\]
\[
P_{\text{max}} = \frac{{52900 \times 10^6 \text{ V}^2}}{{14 \Omega}}
\]
\[
P_{\text{max}} = 3785.71 \times 10^6 \text{ W}
\]
Converting the power to megawatts, we have:
\[
P_{\text{max}} = 3785.71 \text{ MW}
\]
Rounding off the answer to one decimal place, the maximum steady-state power that can be transmitted over the line is approximately 3778.5 MW.
- Sending-end and receiving-end voltages: 230 kV
- Per phase line impedance: 14 ohm
- Load: 200 MW
To find:
- Maximum steady-state power that can be transmitted (MW/phase)
Formula:
The maximum steady-state power that can be transmitted over a transmission line is given by the formula:
\[
P_{\text{max}} = \frac{{V^2}}{{Z}}
\]
where:
- \(P_{\text{max}}\) is the maximum power that can be transmitted
- \(V\) is the sending/receiving voltage
- \(Z\) is the line impedance
Calculation:
Substituting the given values into the formula, we have:
\[
P_{\text{max}} = \frac{{(230 \text{ kV})^2}}{{14 \Omega}}
\]
Converting the voltage to volts and simplifying, we get:
\[
P_{\text{max}} = \frac{{(230 \times 10^3 \text{ V})^2}}{{14 \Omega}}
\]
\[
P_{\text{max}} = \frac{{52900 \times 10^6 \text{ V}^2}}{{14 \Omega}}
\]
\[
P_{\text{max}} = 3785.71 \times 10^6 \text{ W}
\]
Converting the power to megawatts, we have:
\[
P_{\text{max}} = 3785.71 \text{ MW}
\]
Rounding off the answer to one decimal place, the maximum steady-state power that can be transmitted over the line is approximately 3778.5 MW.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer?
Question Description
The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer?.
The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer?.
Solutions for The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer?, a detailed solution for The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer? has been provided alongside types of The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The sending-end and receiving-end voltages of a three-phase transmission line at a 200 MW load are equal at 230 kV. The per phase line impedance is 14 ohm. The maximum steady-state power that can be transmitted (MW/phase) over the line would be _______. (Answer up to one decimal place)Correct answer is '1259.5'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup