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A signal generator having a source resistance of 50 Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor i s _____ µF. (Round off to 2 decimal places).
Correct answer is '2.38 (2.30 to 2.45)'. Can you explain this answer?
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A signal generator having a source resistance of 50Ω is set to g...
Ω is connected to a load resistance of 100 Ω. The voltage measured across the load is 10 V. What is the voltage generated by the signal generator?
To solve this problem, we need to use Ohm's Law and the voltage divider formula. Ohm's Law states that V = IR, where V is voltage, I is current, and R is resistance. The voltage divider formula states that the voltage across a load in a series circuit is proportional to the ratio of the load resistance to the total resistance. In this case, the total resistance is the sum of the source and load resistances.
First, we can use Ohm's Law to find the current in the circuit:
I = V/R = 10/150 = 0.067 A
Next, we can use the voltage divider formula to find the voltage generated by the signal generator:
Vgen = Vload × (Rgen / Rtotal)
= 10 × (50 / 150)
= 3.33 V
Therefore, the voltage generated by the signal generator is 3.33 V.
To solve this problem, we need to use Ohm's Law and the voltage divider formula. Ohm's Law states that V = IR, where V is voltage, I is current, and R is resistance. The voltage divider formula states that the voltage across a load in a series circuit is proportional to the ratio of the load resistance to the total resistance. In this case, the total resistance is the sum of the source and load resistances.
First, we can use Ohm's Law to find the current in the circuit:
I = V/R = 10/150 = 0.067 A
Next, we can use the voltage divider formula to find the voltage generated by the signal generator:
Vgen = Vload × (Rgen / Rtotal)
= 10 × (50 / 150)
= 3.33 V
Therefore, the voltage generated by the signal generator is 3.33 V.
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A signal generator having a source resistance of 50Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor i s _____ µF. (Round off to 2 decimal places).Correct answer is '2.38 (2.30 to 2.45)'. Can you explain this answer?
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A signal generator having a source resistance of 50Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor i s _____ µF. (Round off to 2 decimal places).Correct answer is '2.38 (2.30 to 2.45)'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A signal generator having a source resistance of 50Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor i s _____ µF. (Round off to 2 decimal places).Correct answer is '2.38 (2.30 to 2.45)'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A signal generator having a source resistance of 50Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor i s _____ µF. (Round off to 2 decimal places).Correct answer is '2.38 (2.30 to 2.45)'. Can you explain this answer?.
A signal generator having a source resistance of 50Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor i s _____ µF. (Round off to 2 decimal places).Correct answer is '2.38 (2.30 to 2.45)'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A signal generator having a source resistance of 50Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor i s _____ µF. (Round off to 2 decimal places).Correct answer is '2.38 (2.30 to 2.45)'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A signal generator having a source resistance of 50Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor i s _____ µF. (Round off to 2 decimal places).Correct answer is '2.38 (2.30 to 2.45)'. Can you explain this answer?.
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