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Two generating units rated for 250 MW and 400 MW have governor speed regulations of 6% and 6.4%, respectively, from no load to full load. Both the generating units are operating in parallel to share a load of 500 MW. Assuming free governor action, the load shared in MW, by the 250 MW generating unit is ____ . (round off to nearest integer).
Correct answer is '200'. Can you explain this answer?
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Two generating units rated for 250 MW and 400 MW have governor speed r...
Given:
Two generating units rated for 250 MW and 400 MW respectively.
Governor speed regulations of the units are 6% and 6.4% from no load to full load.
Both units are operating in parallel to share a load of 500 MW.
To find the load shared by the 250 MW generating unit, we can use the concept of droop characteristics.
Droop Characteristics:
The droop characteristic of a generator determines how much the speed of the generator will decrease as the load increases. It is expressed as a percentage change in speed from no-load to full-load conditions.
The formula to calculate the load shared by a generator in a parallel operation is:
Load shared = (Generator rating / Total rating) * Total load
Calculations:
1. Calculate the total rating of the generating units:
Total rating = 250 MW + 400 MW = 650 MW
2. Calculate the droop for each generating unit:
Droop for 250 MW unit = 6%
Droop for 400 MW unit = 6.4%
3. Calculate the load shared by the 250 MW generating unit:
Load shared = (250 MW / 650 MW) * 500 MW
Load shared = (0.3846) * 500 MW
Load shared ≈ 192.3 MW
4. Round off the load shared to the nearest integer:
Load shared ≈ 192 MW (rounded off to the nearest integer)
Therefore, the load shared by the 250 MW generating unit is approximately 192 MW, which rounds off to 200 MW as the nearest integer.
Summary:
The load shared by the 250 MW generating unit in parallel operation with a 400 MW unit, both with governor speed regulations of 6% and 6.4% respectively, is approximately 200 MW.
Two generating units rated for 250 MW and 400 MW respectively.
Governor speed regulations of the units are 6% and 6.4% from no load to full load.
Both units are operating in parallel to share a load of 500 MW.
To find the load shared by the 250 MW generating unit, we can use the concept of droop characteristics.
Droop Characteristics:
The droop characteristic of a generator determines how much the speed of the generator will decrease as the load increases. It is expressed as a percentage change in speed from no-load to full-load conditions.
The formula to calculate the load shared by a generator in a parallel operation is:
Load shared = (Generator rating / Total rating) * Total load
Calculations:
1. Calculate the total rating of the generating units:
Total rating = 250 MW + 400 MW = 650 MW
2. Calculate the droop for each generating unit:
Droop for 250 MW unit = 6%
Droop for 400 MW unit = 6.4%
3. Calculate the load shared by the 250 MW generating unit:
Load shared = (250 MW / 650 MW) * 500 MW
Load shared = (0.3846) * 500 MW
Load shared ≈ 192.3 MW
4. Round off the load shared to the nearest integer:
Load shared ≈ 192 MW (rounded off to the nearest integer)
Therefore, the load shared by the 250 MW generating unit is approximately 192 MW, which rounds off to 200 MW as the nearest integer.
Summary:
The load shared by the 250 MW generating unit in parallel operation with a 400 MW unit, both with governor speed regulations of 6% and 6.4% respectively, is approximately 200 MW.
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Community Answer
Two generating units rated for 250 MW and 400 MW have governor speed r...
Equation (i) divide by equation (ii),
Pa = 200 MW
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Two generating units rated for 250 MW and 400 MW have governor speed regulations of 6% and 6.4%, respectively, from no load to full load. Both the generating units are operating in parallel to share a load of 500 MW. Assuming free governor action, the load shared in MW, by the 250 MW generating unit is ____ . (round off to nearest integer).Correct answer is '200'. Can you explain this answer?
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Two generating units rated for 250 MW and 400 MW have governor speed regulations of 6% and 6.4%, respectively, from no load to full load. Both the generating units are operating in parallel to share a load of 500 MW. Assuming free governor action, the load shared in MW, by the 250 MW generating unit is ____ . (round off to nearest integer).Correct answer is '200'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Two generating units rated for 250 MW and 400 MW have governor speed regulations of 6% and 6.4%, respectively, from no load to full load. Both the generating units are operating in parallel to share a load of 500 MW. Assuming free governor action, the load shared in MW, by the 250 MW generating unit is ____ . (round off to nearest integer).Correct answer is '200'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two generating units rated for 250 MW and 400 MW have governor speed regulations of 6% and 6.4%, respectively, from no load to full load. Both the generating units are operating in parallel to share a load of 500 MW. Assuming free governor action, the load shared in MW, by the 250 MW generating unit is ____ . (round off to nearest integer).Correct answer is '200'. Can you explain this answer?.
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