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Two discrete spherical particles (P and Q) of equal mass density are independently released in water. Particle P and particle Q have diameters of 0.5 mm and 1.0 mm. respectively. Assume Stake’s law is valid.
The drag force on particle Q will be ________ tim es the drag force on particle P. (round off to the nearest integer).
The drag force on particle Q will be ________ tim es the drag force on particle P. (round off to the nearest integer).
Correct answer is '8'. Can you explain this answer?
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Most Upvoted Answer
Two discrete spherical particles (P and Q) of equal mass density are i...
ρ sity of water
ρb = density of particle
Diameter of P = D1 = 0.5 mm
Diameter of Q = D2 = 1 mm
∴
Let’s take basic case of Stake’s law i.e. a particle of diameter d moving, downward in fluid.
FB = Buoyancy force
FD = Drag force
Vs = Setting velocity
W = weigth of particle
Wg = FB + FD
mg - FB = 3πμDVs
(ρb - ρ)Vsphere = 3πμDVs
∵ Volume of sphere,
∴
Now,
∴
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Two discrete spherical particles (P and Q) of equal mass density are i...
Assuming that the particles are solid and have the same mass density, the larger particle Q will have a greater mass than the smaller particle P.
The mass of a spherical particle can be calculated using the formula:
Mass = (4/3) * π * (radius)^3 * density
Since the mass density is the same for both particles, we can compare their masses by comparing their volumes.
The volume of a sphere can be calculated using the formula:
Volume = (4/3) * π * (radius)^3
Let's calculate the volumes of particles P and Q:
Volume of particle P = (4/3) * π * (0.25 mm)^3 ≈ 0.0654 mm^3
Volume of particle Q = (4/3) * π * (0.5 mm)^3 ≈ 0.5236 mm^3
As we can see, the volume of particle Q is approximately 8 times greater than the volume of particle P.
Since the particles have the same mass density, the larger particle Q will have a mass approximately 8 times greater than the smaller particle P.
The mass of a spherical particle can be calculated using the formula:
Mass = (4/3) * π * (radius)^3 * density
Since the mass density is the same for both particles, we can compare their masses by comparing their volumes.
The volume of a sphere can be calculated using the formula:
Volume = (4/3) * π * (radius)^3
Let's calculate the volumes of particles P and Q:
Volume of particle P = (4/3) * π * (0.25 mm)^3 ≈ 0.0654 mm^3
Volume of particle Q = (4/3) * π * (0.5 mm)^3 ≈ 0.5236 mm^3
As we can see, the volume of particle Q is approximately 8 times greater than the volume of particle P.
Since the particles have the same mass density, the larger particle Q will have a mass approximately 8 times greater than the smaller particle P.
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Two discrete spherical particles (P and Q) of equal mass density are independently released in water. Particle P and particle Q have diameters of 0.5 mm and 1.0 mm. respectively. Assume Stake’s law is valid.The drag force on particle Q will be ________ tim es the drag force on particle P. (round off to the nearest integer).Correct answer is '8'. Can you explain this answer?
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Two discrete spherical particles (P and Q) of equal mass density are independently released in water. Particle P and particle Q have diameters of 0.5 mm and 1.0 mm. respectively. Assume Stake’s law is valid.The drag force on particle Q will be ________ tim es the drag force on particle P. (round off to the nearest integer).Correct answer is '8'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Two discrete spherical particles (P and Q) of equal mass density are independently released in water. Particle P and particle Q have diameters of 0.5 mm and 1.0 mm. respectively. Assume Stake’s law is valid.The drag force on particle Q will be ________ tim es the drag force on particle P. (round off to the nearest integer).Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two discrete spherical particles (P and Q) of equal mass density are independently released in water. Particle P and particle Q have diameters of 0.5 mm and 1.0 mm. respectively. Assume Stake’s law is valid.The drag force on particle Q will be ________ tim es the drag force on particle P. (round off to the nearest integer).Correct answer is '8'. Can you explain this answer?.
Two discrete spherical particles (P and Q) of equal mass density are independently released in water. Particle P and particle Q have diameters of 0.5 mm and 1.0 mm. respectively. Assume Stake’s law is valid.The drag force on particle Q will be ________ tim es the drag force on particle P. (round off to the nearest integer).Correct answer is '8'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Two discrete spherical particles (P and Q) of equal mass density are independently released in water. Particle P and particle Q have diameters of 0.5 mm and 1.0 mm. respectively. Assume Stake’s law is valid.The drag force on particle Q will be ________ tim es the drag force on particle P. (round off to the nearest integer).Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two discrete spherical particles (P and Q) of equal mass density are independently released in water. Particle P and particle Q have diameters of 0.5 mm and 1.0 mm. respectively. Assume Stake’s law is valid.The drag force on particle Q will be ________ tim es the drag force on particle P. (round off to the nearest integer).Correct answer is '8'. Can you explain this answer?.
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