Answer:

Introduction:

Inorganic compounds react with NaOH to form water-soluble salt and water. The reaction occurs because of the basic nature of NaOH and acidic nature of inorganic compounds. However, there are some inorganic compounds that do not react with NaOH. The given question asks us to identify the inorganic compound that does not react with NaOH.

Explanation:

Out of the given options, the correct answer is (2) Bi2O3. The explanation for the same is given below:

As2O3:

As2O3 is the chemical formula for arsenic trioxide. When arsenic trioxide reacts with NaOH, it forms sodium arsenite and water. The reaction can be represented as follows:

As2O3 + 6NaOH → 2Na3AsO3 + 3H2O

Therefore, As2O3 reacts with NaOH.

Sb2O3:

Sb2O3 is the chemical formula for antimony trioxide. When antimony trioxide reacts with NaOH, it forms sodium antimonite and water. The reaction can be represented as follows:

Sb2O3 + 6NaOH → 2Na3SbO3 + 3H2O

Therefore, Sb2O3 reacts with NaOH.

SeO2:

SeO2 is the chemical formula for selenium dioxide. When selenium dioxide reacts with NaOH, it forms sodium selenite and water. The reaction can be represented as follows:

SeO2 + 2NaOH → Na2SeO3 + H2O

Therefore, SeO2 reacts with NaOH.

Bi2O3:

Bi2O3 is the chemical formula for bismuth trioxide. When bismuth trioxide reacts with NaOH, it does not form any water-soluble salt. The reaction can be represented as follows:

Bi2O3 + 6NaOH → No reaction

Therefore, Bi2O3 does not react with NaOH.

Conclusion:

Out of the given options, Bi2O3 is the inorganic compound that does not react with NaOH.