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The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
  • a)
    8, 20, 28
  • b)
    16, 28, 36
  • c)
    20, 35, 45
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The present ages of three persons in proportions 4 : 7 : 9. Eight year...
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
⇒ 20x = 80
⇒ x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
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Community Answer
The present ages of three persons in proportions 4 : 7 : 9. Eight year...
Given:
The present ages of three persons are in the ratio 4:7:9.
Let the common ratio be 'x'.
Therefore, the present ages of the three persons can be represented as 4x, 7x, and 9x.

Eight years ago:
The ages of the three persons would have been 4x-8, 7x-8, and 9x-8.

It is given that the sum of their ages eight years ago was 56.
So, we can write the equation:
(4x-8) + (7x-8) + (9x-8) = 56

Simplifying the equation:
4x + 7x + 9x - 24 = 56
20x - 24 = 56
20x = 80
x = 4

Therefore, the common ratio 'x' is 4.

Calculating Present Ages:
The present ages of the three persons can be found by substituting the value of 'x' in the ratio:
4x = 4(4) = 16
7x = 7(4) = 28
9x = 9(4) = 36

Hence, the present ages of the three persons are 16, 28, and 36 years respectively.

Therefore, the correct answer is option B: 16, 28, 36.
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The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).a)8, 20, 28b)16, 28, 36c)20, 35, 45d)None of theseCorrect answer is option 'B'. Can you explain this answer?
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