The sum of ages of 5 children born at the intervals of 3 years each is...
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
⇒ 5x = 20
⇒ x = 4.
∴ Age of the youngest child = x = 4 years.
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The sum of ages of 5 children born at the intervals of 3 years each is...
The Problem:
We are given that 5 children are born at intervals of 3 years each, and the sum of their ages is 50 years. We need to find the age of the youngest child.
Approach:
To solve this problem, we can use the concept of average age. The average age of the 5 children can be calculated by dividing the sum of their ages by the total number of children.
Solution:
1. Let's assume the age of the youngest child is x years.
2. The ages of the other four children can be represented as x+3, x+6, x+9, and x+12 years respectively.
3. According to the problem, the sum of their ages is 50 years, so we can write the equation as:
x + (x+3) + (x+6) + (x+9) + (x+12) = 50
4. Simplifying the equation, we get:
5x + 30 = 50
5x = 20
x = 4
5. Therefore, the age of the youngest child is 4 years.
Final Answer:
The age of the youngest child is 4 years.