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50J of heat is produced each second in a 2 resistor. Find the potential difference across the resistor.?
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50J of heat is produced each second in a 2 resistor. Find the potentia...
Heat = I^2Rt
50 J = I^2 × 2 ×1
50J = 2I^2
50 = 2I^2
I^2 = 50 / 2
I^2 = 25
I = root under 25
I = 5 A
So current is 5 Ampere .
Potential difference i.e, V = IR
V = 5 × 2 = 10 volt
So, potential difference across the resistor = 10 volt
50 J = I^2 × 2 ×1
50J = 2I^2
50 = 2I^2
I^2 = 50 / 2
I^2 = 25
I = root under 25
I = 5 A
So current is 5 Ampere .
Potential difference i.e, V = IR
V = 5 × 2 = 10 volt
So, potential difference across the resistor = 10 volt
Community Answer
50J of heat is produced each second in a 2 resistor. Find the potentia...
**Calculating the Potential Difference across a Resistor**
To calculate the potential difference across a resistor, we need to use the formula:
\[ P = \frac{{V^2}}{{R}} \]
where P is the power, V is the potential difference, and R is the resistance.
Given that the power produced is 50 J (joules) per second and we have two resistors, we can begin by calculating the power produced by each resistor. Since the power is the same across both resistors (in series), we can divide the total power by 2:
\[ P_{\text{total}} = P_1 + P_2 \]
\[ P_1 = P_2 = \frac{{P_{\text{total}}}}{2} = \frac{{50 \, \text{J/s}}}{2} = 25 \, \text{J/s} \]
Now we can rearrange the formula to solve for the potential difference:
\[ V = \sqrt{{P \cdot R}} \]
Since we have the power and need to find the potential difference, we need to find the resistance. Unfortunately, the resistance is not given in the problem. Therefore, we cannot calculate the potential difference without additional information.
To calculate the potential difference across a resistor, we need to use the formula:
\[ P = \frac{{V^2}}{{R}} \]
where P is the power, V is the potential difference, and R is the resistance.
Given that the power produced is 50 J (joules) per second and we have two resistors, we can begin by calculating the power produced by each resistor. Since the power is the same across both resistors (in series), we can divide the total power by 2:
\[ P_{\text{total}} = P_1 + P_2 \]
\[ P_1 = P_2 = \frac{{P_{\text{total}}}}{2} = \frac{{50 \, \text{J/s}}}{2} = 25 \, \text{J/s} \]
Now we can rearrange the formula to solve for the potential difference:
\[ V = \sqrt{{P \cdot R}} \]
Since we have the power and need to find the potential difference, we need to find the resistance. Unfortunately, the resistance is not given in the problem. Therefore, we cannot calculate the potential difference without additional information.
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50J of heat is produced each second in a 2 resistor. Find the potential difference across the resistor.?
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50J of heat is produced each second in a 2 resistor. Find the potential difference across the resistor.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about 50J of heat is produced each second in a 2 resistor. Find the potential difference across the resistor.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 50J of heat is produced each second in a 2 resistor. Find the potential difference across the resistor.?.
50J of heat is produced each second in a 2 resistor. Find the potential difference across the resistor.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about 50J of heat is produced each second in a 2 resistor. Find the potential difference across the resistor.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 50J of heat is produced each second in a 2 resistor. Find the potential difference across the resistor.?.
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