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If a simple harmonic motion is represented by d2x/dt2 + αx = 0, its time period is
- a)2πa
- b)2π√α
- c)2π/α
- d)2π/√α
Correct answer is option 'D'. Can you explain this answer?
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If a simple harmonic motion is represented by d2x/dt2 + αx = 0, ...
D2x/dt2 represents the acceleration of the object undergoing simple harmonic motion.
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If a simple harmonic motion is represented by d2x/dt2 + αx = 0, ...
The expression d2x/dt2 represents the second derivative of the displacement x with respect to time t. This is also known as the acceleration of the object undergoing the simple harmonic motion. In other words, the expression d2x/dt2 describes how the velocity of the object changes over time as it oscillates back and forth around its equilibrium position. The acceleration is directly proportional to the displacement from the equilibrium position and is in the opposite direction to the displacement. This relationship is described by the equation a = -ω^2x, where a is the acceleration, x is the displacement, and ω is the angular frequency of the motion.
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If a simple harmonic motion is represented by d2x/dt2 + αx = 0, its time period isa)2πab)2π√αc)2π/αd)2π/√αCorrect answer is option 'D'. Can you explain this answer?
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