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The force of attraction between two bodies of mass m1 and m2 varies directly as the product of their masses and inversely as the square of the distance between them. If the masses of the bodies and the distance between them are doubled, then the force of attraction will
- a)Be quadrupled
- b)Be doubled
- c)Be halved
- d)Remain the same
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
The force of attraction between two bodies of mass m1and m2varies dire...
Force of attraction F is given by: F 
or, F = K
Here, K is a constant.
When the masses and the distance between them are doubled, the force of attraction F1 will be
F1 = K
= K
Hence, the force of attraction remains unchanged.
∝
or, F = K
Here, K is a constant.
When the masses and the distance between them are doubled, the force of attraction F1 will be
F1 = K
= KHence, the force of attraction remains unchanged.
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Community Answer
The force of attraction between two bodies of mass m1and m2varies dire...
The force of attraction between two bodies of mass m1 and m2 can be calculated using the formula:
F = k * (m1 * m2) / d^2
where F is the force of attraction, k is the proportionality constant, m1 and m2 are the masses of the bodies, and d is the distance between them.
If the masses of the bodies and the distance between them are doubled, we can calculate the new force of attraction using the same formula:
F' = k * ((2m1) * (2m2)) / (2d)^2
Simplifying this expression:
F' = k * (4m1m2) / (4d^2)
= (k * (m1m2)) / d^2
= F
We can see that the new force of attraction is equal to the original force of attraction. Therefore, the correct answer is option D: the force of attraction remains the same.
Explanation:
- The force of attraction between two bodies of mass m1 and m2 varies directly as the product of their masses and inversely as the square of the distance between them.
- This means that as the masses of the bodies increase, the force of attraction will increase, and as the distance between them increases, the force of attraction will decrease.
- When the masses and the distance are both doubled, the increase in force due to the increased masses is exactly offset by the decrease in force due to the increased distance.
- The proportionality constant k remains the same in this scenario.
- Therefore, the force of attraction will remain the same when both the masses and the distance are doubled.
F = k * (m1 * m2) / d^2
where F is the force of attraction, k is the proportionality constant, m1 and m2 are the masses of the bodies, and d is the distance between them.
If the masses of the bodies and the distance between them are doubled, we can calculate the new force of attraction using the same formula:
F' = k * ((2m1) * (2m2)) / (2d)^2
Simplifying this expression:
F' = k * (4m1m2) / (4d^2)
= (k * (m1m2)) / d^2
= F
We can see that the new force of attraction is equal to the original force of attraction. Therefore, the correct answer is option D: the force of attraction remains the same.
Explanation:
- The force of attraction between two bodies of mass m1 and m2 varies directly as the product of their masses and inversely as the square of the distance between them.
- This means that as the masses of the bodies increase, the force of attraction will increase, and as the distance between them increases, the force of attraction will decrease.
- When the masses and the distance are both doubled, the increase in force due to the increased masses is exactly offset by the decrease in force due to the increased distance.
- The proportionality constant k remains the same in this scenario.
- Therefore, the force of attraction will remain the same when both the masses and the distance are doubled.
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The force of attraction between two bodies of mass m1and m2varies directly as the product of their masses and inversely as the square of the distance between them. If the masses of the bodies and the distance between them are doubled, then the force of attraction willa)Be quadrupledb)Be doubledc)Be halvedd)Remain the sameCorrect answer is option 'D'. Can you explain this answer?
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