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Convert the following infix expression to postfix expression using stack:
(A+B*(C-D)^E+(F/G)^H-I)
  • a)
    ABCD-E^*+FG/H^+I-
  • b)
    ABCD-E^*+FG/H^I-+
  • c)
    AB+CD-E^*FG/H^+I-
  • d)
    AB+CD-E^*FG/H^I-+
Correct answer is option 'A'. Can you explain this answer?
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Convert the following infix expression to postfix expression using sta...
The conversion using stack is as follows:

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Convert the following infix expression to postfix expression using sta...
Converting Infix Expression to Postfix Expression using Stack

To convert an infix expression to a postfix expression, we need to follow the rules of the operator precedence and the use of parentheses. We will use a stack to help us in the conversion process.

Given Infix Expression:
A B*(C-D)^E (F/G)^H-I

Steps to Convert:

1. Initialize an empty stack to hold the operators temporarily.

2. Scan the infix expression from left to right and perform the following steps for each element:

a. If the element is an operand (A-Z), append it directly to the postfix expression.

b. If the element is an opening parenthesis "(", push it onto the stack.

c. If the element is a closing parenthesis ")", pop all operators from the stack and append them to the postfix expression until an opening parenthesis is encountered. Discard the opening parenthesis.

d. If the element is an operator (+-*/^), check the operator precedence and associativity rules:

i. If the stack is empty or contains an opening parenthesis, push the operator onto the stack.

ii. If the operator has higher precedence than the top of the stack, push it onto the stack.

iii. If the operator has lower precedence than or equal precedence to the top of the stack, pop operators from the stack and append them to the postfix expression until a lower precedence operator is encountered or the stack becomes empty. Then push the current operator onto the stack.

3. After scanning the entire infix expression, pop any remaining operators from the stack and append them to the postfix expression.

Conversion Process:

Let's follow the above steps to convert the given infix expression to postfix expression:

Step 1: Initialize an empty stack.

Step 2: Scan the infix expression from left to right.

Element: A
Stack:
Postfix: A

Element:
Stack:
Postfix: A

Element: B
Stack:
Postfix: AB

Element: *
Stack: *
Postfix: AB

Element: (
Stack: *, (
Postfix: AB

Element: C
Stack: *, (
Postfix: ABC

Element: -
Stack: *, (
Postfix: ABC-

Element: D
Stack: *, (
Postfix: ABC-D

Element: )
Stack: *
Postfix: ABC-D*

Element: ^
Stack: ^, *
Postfix: ABC-D*

Element: E
Stack: ^, *
Postfix: ABC-D*E

Element:
Stack:
Postfix: ABC-D*E^

Element: (
Stack: (
Postfix: ABC-D*E^

Element: F
Stack: (
Postfix: ABC-D*E^F

Element: /
Stack: /, (
Postfix: ABC-D*E^F/

Element: G
Stack: /, (
Postfix: ABC-D*E^FG/

Element: )
Stack:
Postfix: ABC-D*E^FG/

Element: ^
Stack: ^
Post
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