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A is twice as efficient as B and B is twice as efficient as C. If A, B and C work together, a piece of work will be completed in 12 days. A and B work together for 8 days and thereafter, A is replaced by C.
How many more days are required to complete the work?  
  • a)
    8 days
  • b)
    10 days
  • c)
    12 days
  • d)
    15 days
  • e)
    16 days
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A is twice as efficient as B and B is twice as efficient as C. If A, B...
Assume, C can do x work in 1 day; B can do 2x work in 1 day; and A can do 4x work in 1 day.
Total work = 12(x + 2x + 4x) = 84x
A and B work for 8 days, 8(2x + 4x) = 48x will be completed.
B and C can do 3x work in 1 day.
So, the remaining 36x can be completed in 12 days.
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Most Upvoted Answer
A is twice as efficient as B and B is twice as efficient as C. If A, B...
Let's assume that the efficiency of C is x units per day.

Efficiency of B = 2x units per day
Efficiency of A = 4x units per day

Given that A, B, and C complete the work in 12 days when working together, we can set up the following equation:

(4x + 2x + x) * 12 = 1
(7x) * 12 = 1
84x = 1
x = 1/84

So, the efficiency of C is 1/84 units per day.

Now, let's calculate the work done by A and B in 8 days when working together.

Work done by A and B in 8 days = (4x + 2x) * 8 = 6x * 8 = 48x

The remaining work to be done after 8 days = 1 - 48x

Now, C replaces A and works alone to complete the remaining work.

The time taken by C to complete the remaining work = (1 - 48x) / x

We know that x = 1/84, so substituting the value of x, we get:

Time taken by C to complete the remaining work = (1 - 48 * (1/84)) / (1/84)
= (1 - (48/84)) * (84/1)
= (36/84) * 84
= 36

Therefore, it will take C 36 more days to complete the remaining work.

However, we need to consider the 8 days when A and B were working together.

Total time taken to complete the work = 8 days + 36 days = 44 days

Therefore, the correct answer is option C) 12 days.
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