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A and B throw 2 dices. If A throws sum of 9, then B's chance of throwing higher sum number is

  • a)
    1/6

  • b)
    1/2

  • c)
    1/3

  • d)
    1/8

Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A and B throw 2 dices. If A throws sum of 9, then Bs chance of throwin...
Explanation:

Given Information:
When A throws 9, it means the total of the two dice is 9.

Possible Outcomes for A throwing 9:
When A throws 9, the possible outcomes are (3,6), (4,5), (5,4), and (6,3).

Chances of B throwing a higher number:
Out of the 4 possible outcomes, there are 3 outcomes where B can throw a higher number than 9.
So, the probability of B throwing a higher number is 3 out of 6 possible outcomes (since there are 6 possible outcomes when two dice are thrown).

Calculation:
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 3/6
Probability = 1/2
Therefore, the chances of B throwing a higher number when A throws 9 is 1/2.

Conclusion:
The correct answer is option 'A' (1/6) as B has a 1/6 chance of throwing a higher number when A throws 9.
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Community Answer
A and B throw 2 dices. If A throws sum of 9, then Bs chance of throwin...
Let, n = Total number of ways = 6 x 6 = 36 m = number of favourable ways =3+2+1=6
∴ 
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A and B throw 2 dices. If A throws sum of 9, then Bs chance of throwing higher sum number isa)1/6b)1/2c)1/3d)1/8Correct answer is option 'A'. Can you explain this answer?
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