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Both A and B throw a dice. The chance that B throws a number higher than that thrown by A is
- a)1/2
- b)21/36
- c)15/36
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Both A and B throw a dice. The chance that B throws a number higher th...
To find the probability that B throws a number higher than A, we need to consider all the possible outcomes of their dice throws.
There are a total of 6 outcomes for each throw of the dice, numbered from 1 to 6.
Let's analyze the possible outcomes step by step:
Step 1: Determine the outcomes for A's throw
- A can throw any number from 1 to 6, so there are 6 possible outcomes for A's throw.
Step 2: Determine the outcomes for B's throw
- B can also throw any number from 1 to 6, so there are 6 possible outcomes for B's throw.
Step 3: Analyze the favorable outcomes
- We need to find the outcomes where B throws a number higher than A.
- If A throws a 1, B can throw any number from 2 to 6. So, there are 5 favorable outcomes.
- If A throws a 2, B can throw any number from 3 to 6. So, there are 4 favorable outcomes.
- If A throws a 3, B can throw any number from 4 to 6. So, there are 3 favorable outcomes.
- If A throws a 4, B can throw any number from 5 to 6. So, there are 2 favorable outcomes.
- If A throws a 5, B can only throw a 6. So, there is 1 favorable outcome.
- If A throws a 6, there are no favorable outcomes since B cannot throw a number higher than 6.
Step 4: Calculate the probability
- The total number of outcomes for A's throw is 6, and the total number of outcomes for B's throw is also 6.
- The total number of favorable outcomes is 5 + 4 + 3 + 2 + 1 = 15.
Using the formula for probability:
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 15 / (6 * 6) = 15 / 36
Therefore, the correct answer is option C) 15/36.
There are a total of 6 outcomes for each throw of the dice, numbered from 1 to 6.
Let's analyze the possible outcomes step by step:
Step 1: Determine the outcomes for A's throw
- A can throw any number from 1 to 6, so there are 6 possible outcomes for A's throw.
Step 2: Determine the outcomes for B's throw
- B can also throw any number from 1 to 6, so there are 6 possible outcomes for B's throw.
Step 3: Analyze the favorable outcomes
- We need to find the outcomes where B throws a number higher than A.
- If A throws a 1, B can throw any number from 2 to 6. So, there are 5 favorable outcomes.
- If A throws a 2, B can throw any number from 3 to 6. So, there are 4 favorable outcomes.
- If A throws a 3, B can throw any number from 4 to 6. So, there are 3 favorable outcomes.
- If A throws a 4, B can throw any number from 5 to 6. So, there are 2 favorable outcomes.
- If A throws a 5, B can only throw a 6. So, there is 1 favorable outcome.
- If A throws a 6, there are no favorable outcomes since B cannot throw a number higher than 6.
Step 4: Calculate the probability
- The total number of outcomes for A's throw is 6, and the total number of outcomes for B's throw is also 6.
- The total number of favorable outcomes is 5 + 4 + 3 + 2 + 1 = 15.
Using the formula for probability:
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 15 / (6 * 6) = 15 / 36
Therefore, the correct answer is option C) 15/36.
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Both A and B throw a dice. The chance that B throws a number higher than that thrown by A isa)1/2b)21/36c)15/36d)none of theseCorrect answer is option 'C'. Can you explain this answer?
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