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Both A and B throw a dice. The chance that B throws a number not less than that thrown by A is
  • a)
    1/2
  • b)
    15/36
  • c)
    21/36
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Both A and B throw a dice. The chance that B throws a number not less ...
c) 21/36
If both A and B throw a dice, there are 36 possible outcomes in total: 6 possibilities for what A throws and 6 possibilities for what B throws. Of these 36 outcomes, 15 of them result in B throwing a number that is not less than the number thrown by A. Therefore, the probability that B throws a number not less than that thrown by A is 15/36, which is approximately 41.7%.

To find the probability of this event, we can consider each of the possible outcomes separately. For example, if A throws a 1 and B throws a 2, then B has thrown a number not less than that thrown by A. If A throws a 3 and B throws a 3, then B has thrown a number not less than that thrown by A. If A throws a 4 and B throws a 6, then B has thrown a number not less than that thrown by A. There are a total of 15 such outcomes.

The probability that B throws a number less than that thrown by A is 21/36, or approximately 58.3%. This is the complementary probability to the probability that B throws a number not less than that thrown by A. The complementary probability is the probability of the event not occurring. In this case, the event "B throws a number not less than that thrown by A" is not occurring if B throws a number less than that thrown by A. The sum of the probability of an event occurring and the probability of the event not occurring is always 1, so the probability of an event occurring plus the complementary probability of the event is always equal to 1.

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Most Upvoted Answer
Both A and B throw a dice. The chance that B throws a number not less ...
Solution:
When both A and B throw a dice, then the possible outcomes for each of them are 1, 2, 3, 4, 5, 6.

Total number of possible outcomes:
The total number of possible outcomes when A and B throw a dice is 6 x 6 = 36.

Favorable outcomes:
For B to throw a number not less than that thrown by A, there are two cases to consider:

Case 1: When A throws 1
In this case, the favorable outcomes for B are 1, 2, 3, 4, 5, 6. B can throw any number from 1 to 6, which means there are 6 favorable outcomes for B.

Case 2: When A throws a number greater than 1
In this case, the favorable outcomes for B are the numbers greater than or equal to that thrown by A. For example, if A throws 2, then the favorable outcomes for B are 2, 3, 4, 5, 6. B can throw any number from A to 6, which means there are (7 - A) favorable outcomes for B.

Therefore, the total number of favorable outcomes is:
Favorable outcomes = (6) + (5 + 4 + 3 + 2 + 1) + (4 + 3 + 2 + 1) + (3 + 2 + 1) + (2 + 1) + (1)
Favorable outcomes = 21

Probability:
The probability of B throwing a number not less than that thrown by A is the ratio of favorable outcomes to total outcomes:
Probability = Favorable outcomes/Total outcomes
Probability = 21/36
Probability = 7/12

Therefore, the answer is option (c) 21/36.
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Both A and B throw a dice. The chance that B throws a number not less than that thrown by A isa)1/2b)15/36c)21/36d)none of theseCorrect answer is option 'C'. Can you explain this answer?
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