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The order of energy absorbed which is responsible for the color of complexes
(A) [Ni(H2O)2(en)2]2+
(B) [Ni(H2O)4(en)]2+
(C) [Ni(en)3]2+
(A) [Ni(H2O)2(en)2]2+
(B) [Ni(H2O)4(en)]2+
(C) [Ni(en)3]2+
- a)(C)>(B)>(A)
- b)(C)>(A)>(B)
- c)(B)>(A)>(C)
- d)(A)>(B)>(C)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The order of energy absorbed which is responsible for the color of com...
The order of energy absorbed responsible for the color of complexes is:
(C) [Ni(en)3]2 > (A) [Ni(H2O)2(en)2]2 > (B) [Ni(H2O)4(en)]2
In general, the color of a complex is determined by the energy difference between the ground state and the excited state. The higher the energy difference, the higher the energy absorbed, and the more intense the color.
In complex (C) [Ni(en)3]2, the ligand en (ethylenediamine) is a stronger ligand compared to H2O, and it forms a more stable complex with Ni. This results in a larger energy difference between the ground state and the excited state, leading to a more intense color.
In complex (A) [Ni(H2O)2(en)2]2, the ligand en is still present but in lower quantity compared to (C), and there are also two H2O ligands. The presence of H2O ligands weakens the overall stability of the complex, resulting in a slightly lower energy difference and a less intense color compared to (C).
In complex (B) [Ni(H2O)4(en)]2, all four ligands are H2O, which are weaker ligands compared to en. This leads to a lower energy difference between the ground state and the excited state, resulting in a less intense color compared to both (C) and (A).
(C) [Ni(en)3]2 > (A) [Ni(H2O)2(en)2]2 > (B) [Ni(H2O)4(en)]2
In general, the color of a complex is determined by the energy difference between the ground state and the excited state. The higher the energy difference, the higher the energy absorbed, and the more intense the color.
In complex (C) [Ni(en)3]2, the ligand en (ethylenediamine) is a stronger ligand compared to H2O, and it forms a more stable complex with Ni. This results in a larger energy difference between the ground state and the excited state, leading to a more intense color.
In complex (A) [Ni(H2O)2(en)2]2, the ligand en is still present but in lower quantity compared to (C), and there are also two H2O ligands. The presence of H2O ligands weakens the overall stability of the complex, resulting in a slightly lower energy difference and a less intense color compared to (C).
In complex (B) [Ni(H2O)4(en)]2, all four ligands are H2O, which are weaker ligands compared to en. This leads to a lower energy difference between the ground state and the excited state, resulting in a less intense color compared to both (C) and (A).
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The order of energy absorbed which is responsible for the color of com...
(A) [Ni(H2O)2(en)2]2+
(B) [Ni(H2O)4(en)]2+
(C) [Ni(en)3]2+
en is SFL (strong field ligand)
As the number of en (strong ligand) increase splitting also increases.
So, Δ0 increases.
i.e. maximum energy will be absorbed in case of option C.
So the order is C > A > B
(B) [Ni(H2O)4(en)]2+
(C) [Ni(en)3]2+
en is SFL (strong field ligand)
As the number of en (strong ligand) increase splitting also increases.
So, Δ0 increases.
i.e. maximum energy will be absorbed in case of option C.
So the order is C > A > B
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The order of energy absorbed which is responsible for the color of complexes(A) [Ni(H2O)2(en)2]2+(B) [Ni(H2O)4(en)]2+(C) [Ni(en)3]2+a)(C)>(B)>(A)b)(C)>(A)>(B)c)(B)>(A)>(C)d)(A)>(B)>(C)Correct answer is option 'B'. Can you explain this answer?
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