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A 24kW, 250V, 1600 rpm, separately excited DC generator has an armature resistance of 0.1 Ω. The machine is first, run at rated speed and the field current is adjusted to give an open circuit voltage of 260V. When the generator is loaded to deliver its rated current, the speed of the driving motor (prime mover) is found to be 1500 rpm. Assuming that the field current remains unaltered, compute the terminal voltage of the generator.?
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A 24kW, 250V, 1600 rpm, separately excited DC generator has an armatur...
Calculation of Terminal Voltage of Separately Excited DC Generator


Given Parameters


  • Power Output (P) = 24 kW

  • Terminal Voltage at No Load (E0) = 260V

  • Armature Resistance (Ra) = 0.1Ω

  • Rated Speed (N) = 1600 rpm

  • Field Current (If) is unaltered

  • Rated Current (I) = ?

  • Speed at Rated Load (Nl) = 1500 rpm



Calculation of Rated Current

Given that Power Output (P) = 24 kW, we can use the formula:
P = E0 × I
Therefore, I = P ÷ E0
I = 24,000 W ÷ 260 V
I = 92.3 A
Hence, the Rated Current (I) is 92.3 A.

Calculation of Armature Voltage Drop

The armature voltage drop (Vd) can be calculated using Ohm's Law:
Vd = I × Ra
Vd = 92.3 A × 0.1 Ω
Vd = 9.23 V

Calculation of Terminal Voltage

The terminal voltage (E) of the generator can be calculated using the formula:
E = E0 - Vd
E = 260 V - 9.23 V
E = 250.77 V

Explanation

The given DC generator is a separately excited generator, which means that the field current (If) is supplied from an external source. When the generator is run at rated speed, the field current is adjusted to give an open circuit voltage of 260V. At this stage, there is no load on the generator, and hence the terminal voltage is equal to the open circuit voltage (E0).

When the generator is loaded to deliver its rated current of 92.3 A, the armature resistance (Ra) causes a voltage drop of 9.23 V. This voltage drop is known as the armature voltage drop (Vd).

As the field current remains unaltered, the terminal voltage (E) can be calculated by subtracting the armature voltage drop (Vd) from the open circuit voltage (E0). Hence, the terminal voltage of the generator under rated load conditions is 250.77 V.
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A 24kW, 250V, 1600 rpm, separately excited DC generator has an armature resistance of 0.1 Ω. The machine is first, run at rated speed and the field current is adjusted to give an open circuit voltage of 260V. When the generator is loaded to deliver its rated current, the speed of the driving motor (prime mover) is found to be 1500 rpm. Assuming that the field current remains unaltered, compute the terminal voltage of the generator.?
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A 24kW, 250V, 1600 rpm, separately excited DC generator has an armature resistance of 0.1 Ω. The machine is first, run at rated speed and the field current is adjusted to give an open circuit voltage of 260V. When the generator is loaded to deliver its rated current, the speed of the driving motor (prime mover) is found to be 1500 rpm. Assuming that the field current remains unaltered, compute the terminal voltage of the generator.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A 24kW, 250V, 1600 rpm, separately excited DC generator has an armature resistance of 0.1 Ω. The machine is first, run at rated speed and the field current is adjusted to give an open circuit voltage of 260V. When the generator is loaded to deliver its rated current, the speed of the driving motor (prime mover) is found to be 1500 rpm. Assuming that the field current remains unaltered, compute the terminal voltage of the generator.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 24kW, 250V, 1600 rpm, separately excited DC generator has an armature resistance of 0.1 Ω. The machine is first, run at rated speed and the field current is adjusted to give an open circuit voltage of 260V. When the generator is loaded to deliver its rated current, the speed of the driving motor (prime mover) is found to be 1500 rpm. Assuming that the field current remains unaltered, compute the terminal voltage of the generator.?.
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