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If the solubility of PbCl₂ at 25oC is 6.3 x 10⁻3 mole/litre, its solubility product at that temperature is
- a)(6.3 x 10⁻3) x (6.3 x10⁻3)2
- b)(6.3 x 10⁻3) x (12.6 x 10⁻3)2
- c)(6.3 x 10⁻3) x (12.6 x 10⁻3)
- d)(12.6 x 10⁻3) x (12.6 x10⁻3)
Correct answer is option 'B'. Can you explain this answer?
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If the solubility of PbCl at 25oC is 6.3 x 103 mole/litre, its solubil...
Solubility product (Ksp) is the product of the molar concentration of the ions in a solution at equilibrium raised to the power of their stoichiometric coefficients. The expression for the solubility product of PbCl2 is:
PbCl2 ⇌ Pb2+ + 2Cl-
Ksp = [Pb2+][Cl-]^2
Given that the solubility of PbCl2 at 25°C is 6.3 x 10^3 mol/L, we can use this value to find the molar concentration of Pb2+ and Cl- ions in the solution.
Molar concentration of Pb2+ = solubility of PbCl2 = 6.3 x 10^3 mol/L
Molar concentration of Cl- = 2 x solubility of PbCl2 = 2 x 6.3 x 10^3 mol/L = 12.6 x 10^3 mol/L
Substituting these values into the expression for Ksp, we get:
Ksp = [6.3 x 10^3][12.6 x 10^3]^2 = 1.00 x 10^-5 mol^3/L^3
Therefore, the correct answer is option B, (6.3 x 10^3) x (12.6 x 10^3)^2.
PbCl2 ⇌ Pb2+ + 2Cl-
Ksp = [Pb2+][Cl-]^2
Given that the solubility of PbCl2 at 25°C is 6.3 x 10^3 mol/L, we can use this value to find the molar concentration of Pb2+ and Cl- ions in the solution.
Molar concentration of Pb2+ = solubility of PbCl2 = 6.3 x 10^3 mol/L
Molar concentration of Cl- = 2 x solubility of PbCl2 = 2 x 6.3 x 10^3 mol/L = 12.6 x 10^3 mol/L
Substituting these values into the expression for Ksp, we get:
Ksp = [6.3 x 10^3][12.6 x 10^3]^2 = 1.00 x 10^-5 mol^3/L^3
Therefore, the correct answer is option B, (6.3 x 10^3) x (12.6 x 10^3)^2.
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If the solubility of PbCl at 25oC is 6.3 x 103 mole/litre, its solubility product at that temperature isa)(6.3 x 103) x (6.3 x103)2b)(6.3 x 103) x (12.6 x 103)2c)(6.3 x 103) x (12.6 x 103)d)(12.6 x 103) x (12.6 x103)Correct answer is option 'B'. Can you explain this answer?
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If the solubility of PbCl at 25oC is 6.3 x 103 mole/litre, its solubility product at that temperature isa)(6.3 x 103) x (6.3 x103)2b)(6.3 x 103) x (12.6 x 103)2c)(6.3 x 103) x (12.6 x 103)d)(12.6 x 103) x (12.6 x103)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If the solubility of PbCl at 25oC is 6.3 x 103 mole/litre, its solubility product at that temperature isa)(6.3 x 103) x (6.3 x103)2b)(6.3 x 103) x (12.6 x 103)2c)(6.3 x 103) x (12.6 x 103)d)(12.6 x 103) x (12.6 x103)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the solubility of PbCl at 25oC is 6.3 x 103 mole/litre, its solubility product at that temperature isa)(6.3 x 103) x (6.3 x103)2b)(6.3 x 103) x (12.6 x 103)2c)(6.3 x 103) x (12.6 x 103)d)(12.6 x 103) x (12.6 x103)Correct answer is option 'B'. Can you explain this answer?.
If the solubility of PbCl at 25oC is 6.3 x 103 mole/litre, its solubility product at that temperature isa)(6.3 x 103) x (6.3 x103)2b)(6.3 x 103) x (12.6 x 103)2c)(6.3 x 103) x (12.6 x 103)d)(12.6 x 103) x (12.6 x103)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If the solubility of PbCl at 25oC is 6.3 x 103 mole/litre, its solubility product at that temperature isa)(6.3 x 103) x (6.3 x103)2b)(6.3 x 103) x (12.6 x 103)2c)(6.3 x 103) x (12.6 x 103)d)(12.6 x 103) x (12.6 x103)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the solubility of PbCl at 25oC is 6.3 x 103 mole/litre, its solubility product at that temperature isa)(6.3 x 103) x (6.3 x103)2b)(6.3 x 103) x (12.6 x 103)2c)(6.3 x 103) x (12.6 x 103)d)(12.6 x 103) x (12.6 x103)Correct answer is option 'B'. Can you explain this answer?.
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