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The 4 th term of AP is zero, prove that 25th term of AP is three times the 11th term?
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The 4 th term of AP is zero, prove that 25th term of AP is three times...
Proof: 4th term of AP is zero
Let the AP be represented by a, a + d, a + 2d, a + 3d, .....
Given that the 4th term of the AP is zero.
Therefore, a + 3d = 0
=> a = -3d

Prove that 25th term of AP is three times the 11th term
To prove: 25th term = 3 x 11th term

Method 1: Using the formula for nth term of an AP
The formula for nth term of an AP is given by: a + (n-1)d
Substituting a = -3d and n = 25, we get:
25th term = -3d + 24d = 21d
Substituting a = -3d and n = 11, we get:
11th term = -3d + 10d = 7d
Therefore, 25th term = 3 x 7th term = 21d = 3 x 7d = 3 x 11th term

Method 2: Using the common difference of the AP
We know that the 11th term of the AP is a + 10d and the 25th term of the AP is a + 24d.
Substituting a = -3d, we get:
11th term = -3d + 10d = 7d
25th term = -3d + 24d = 21d
Therefore, 25th term = 3 x 7th term = 21d = 3 x 7d = 3 x 11th term

Hence, we have proved that the 25th term of the AP is three times the 11th term.
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The 4 th term of AP is zero, prove that 25th term of AP is three times the 11th term?
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