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Determine the number of filter unit required for a population of 50,000 whose per capita demand is 150 Ipcd. Rate of filtration is 180 liters/ hr/ sq.m, area of each unit is 100 sq.m and running for 8 hr per day (1) 4nos (2) 6nos (3) 8nos (4) 10 nos?
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Determine the number of filter unit required for a population of 50,00...
Solution:
Given data:
Population = 50,000
Per capita demand = 150 Ipcd
Rate of filtration = 180 liters/ hr/ sq.m
Area of each unit = 100 sq.m
Running hours per day = 8 hr
We are supposed to determine the number of filter units required for a population of 50,000 whose per capita demand is 150 Ipcd.
Calculation:
Total water demand = Population × Per capita demand
= 50,000 × 150
= 7500000 liters/ day
Area required for filtration unit = Total water demand/ (Rate of filtration × Running hours)
= 7500000/ (180 × 8)
= 5208.33 sq.m
Number of filter units required = Total area required/ Area of each unit
= 5208.33/ 100
= 52.08 ≈ 53 (approx.)
Answer:
Therefore, the number of filter units required for a population of 50,000 whose per capita demand is 150 Ipcd, running for 8 hr per day with a rate of filtration of 180 liters/ hr/ sq.m and an area of each unit of 100 sq.m is 53 (approx.)
Note: It is always better to have one or two additional units as a standby in case of any emergency or maintenance work. Hence, the number of filter units can be rounded off to the next even number, i.e., 54.
Given data:
Population = 50,000
Per capita demand = 150 Ipcd
Rate of filtration = 180 liters/ hr/ sq.m
Area of each unit = 100 sq.m
Running hours per day = 8 hr
We are supposed to determine the number of filter units required for a population of 50,000 whose per capita demand is 150 Ipcd.
Calculation:
Total water demand = Population × Per capita demand
= 50,000 × 150
= 7500000 liters/ day
Area required for filtration unit = Total water demand/ (Rate of filtration × Running hours)
= 7500000/ (180 × 8)
= 5208.33 sq.m
Number of filter units required = Total area required/ Area of each unit
= 5208.33/ 100
= 52.08 ≈ 53 (approx.)
Answer:
Therefore, the number of filter units required for a population of 50,000 whose per capita demand is 150 Ipcd, running for 8 hr per day with a rate of filtration of 180 liters/ hr/ sq.m and an area of each unit of 100 sq.m is 53 (approx.)
Note: It is always better to have one or two additional units as a standby in case of any emergency or maintenance work. Hence, the number of filter units can be rounded off to the next even number, i.e., 54.
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Determine the number of filter unit required for a population of 50,000 whose per capita demand is 150 Ipcd. Rate of filtration is 180 liters/ hr/ sq.m, area of each unit is 100 sq.m and running for 8 hr per day (1) 4nos (2) 6nos (3) 8nos (4) 10 nos?
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Determine the number of filter unit required for a population of 50,000 whose per capita demand is 150 Ipcd. Rate of filtration is 180 liters/ hr/ sq.m, area of each unit is 100 sq.m and running for 8 hr per day (1) 4nos (2) 6nos (3) 8nos (4) 10 nos? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Determine the number of filter unit required for a population of 50,000 whose per capita demand is 150 Ipcd. Rate of filtration is 180 liters/ hr/ sq.m, area of each unit is 100 sq.m and running for 8 hr per day (1) 4nos (2) 6nos (3) 8nos (4) 10 nos? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the number of filter unit required for a population of 50,000 whose per capita demand is 150 Ipcd. Rate of filtration is 180 liters/ hr/ sq.m, area of each unit is 100 sq.m and running for 8 hr per day (1) 4nos (2) 6nos (3) 8nos (4) 10 nos?.
Determine the number of filter unit required for a population of 50,000 whose per capita demand is 150 Ipcd. Rate of filtration is 180 liters/ hr/ sq.m, area of each unit is 100 sq.m and running for 8 hr per day (1) 4nos (2) 6nos (3) 8nos (4) 10 nos? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Determine the number of filter unit required for a population of 50,000 whose per capita demand is 150 Ipcd. Rate of filtration is 180 liters/ hr/ sq.m, area of each unit is 100 sq.m and running for 8 hr per day (1) 4nos (2) 6nos (3) 8nos (4) 10 nos? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the number of filter unit required for a population of 50,000 whose per capita demand is 150 Ipcd. Rate of filtration is 180 liters/ hr/ sq.m, area of each unit is 100 sq.m and running for 8 hr per day (1) 4nos (2) 6nos (3) 8nos (4) 10 nos?.
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