Aak kaam krna tum aak formula hai x square or y square yee formula pr tum q KO x mn lena or y KO r usske bdd cross multiple kr Lena nikhl jayega

Understanding the Problem
To find the coordinates of point P, we know:
- The x-coordinate of P is twice the y-coordinate: x = 2y.
- P is equidistant from Q(2, -5) and R(-3, 6).
We will denote the coordinates of P as (x, y).
Using the Distance Formula
The distance between two points (x1, y1) and (x2, y2) is given by the formula:
Distance = √((x2 - x1)² + (y2 - y1)²).
We need to set the distances from P to Q and P to R equal to each other.
Setting Up the Equations
1. Distance from P to Q:
- D(P, Q) = √((x - 2)² + (y + 5)²).
2. Distance from P to R:
- D(P, R) = √((x + 3)² + (y - 6)²).
Since P is equidistant from Q and R:
√((x - 2)² + (y + 5)²) = √((x + 3)² + (y - 6)²).
Substituting x in Terms of y
Since x = 2y, substitute into the distance equation:
√(((2y - 2)² + (y + 5)²) = √(((2y + 3)² + (y - 6)²).
Simplifying the Equation
Square both sides to eliminate the square roots:
(2y - 2)² + (y + 5)² = (2y + 3)² + (y - 6)².
Expanding both sides will yield a quadratic equation. Solve for y.
Finding Coordinates of P
Once you solve for y, substitute back to find x using x = 2y.
After calculations, the coordinates of P will be determined.
Conclusion
The coordinates of point P can be found through substitution and solving the resulting equation, leading to the desired point that is equidistant from Q and R.